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On the circular runway, a starts from point a and B starts from point B at the same time and goes in the opposite direction. After 8 minutes, the two people meet. After 6 minutes, a arrives at point B, and after 10 minutes, the two people meet again. How many minutes does it take for a circle runway? Let the perimeter of the runway be "1" B 8 points of the journey, a line of 6 points, so the speed ratio of a and B is: 8:6 = 4:3 From the first meeting to the second meeting: 6 + 10 = 16 points, they had a whole journey So the sum of their speed is 1 / 16 That is, the speed of a is: 1 / 16 / (4 + 3) * 4 = 1 / 28 So the time of a week is: 1 / (1 / 28) = 28 points Is this the right way? How?
That's right
If a person walks together for one week, 6 + 10 = 16 points, then 8 points walk together for half a week, that is, a and B are at both ends of the diameter at the beginning. A person walks for half a week, 8 + 6 = 14 points, and a week, 14 × 2 = 28 points
A: it takes 28 points for a week
I'm a teacher. Thank you
It takes 10 minutes for a to go from the East Village to the West Village, and 15 minutes for B to go from the West Village to the East Village
A: the distance between the two villages is 750 meters
Party A and Party B set out from both sides of AB at the same time. It takes 10 minutes for Party A to complete the whole journey and 15 minutes for Party B. as a result, they meet at 2100 meters from the midpoint?
Find out the meeting time first
1 ÷ (1 / 10 + 1 / 15) = 6 minutes
When we met, a went
1/10×6=0.6
The whole process is
2100 ÷ (0.6-1 / 2) = 21000m
It takes 10 minutes for a to go from the East Village to the West Village, and 15 minutes for B to go from the West Village to the East Village
Find the distance between the two villages.
Let the velocities of a and B be x and Y respectively
Then 10 * x + 15y = s (1)
(x+y)*t=s (2)
s/2 - y*t=150 (3)
Combined with several formulas, s = 1500m
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