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The two cars leave from two places at the same time and meet each other in three hours. The speed ratio of car a and car B is 5:4, and the distance between the two places is 270km
270 △ 3 = 90 (km), 5 + 4 = 9, 90 × 59 = 50 (km), 90 × 49 = 40 (km). A: the speed of car a is 50 km / h, and that of car B is 40 km / h
A and B start from AB and meet each other two hours later. After meeting, they continue to leave. When a arrives at B, B is 60km away from A. what's the speed of a and B?
First of all, you didn't specify the grade, so the equation is preferred. Let the distance of AB be s, and the speed of a and B vehicles be V1 and V2 respectively, then: 1. From 2 hours, s = 2 (V1 + V2) 2. From a to B, B is 60 km away from a, and the time of a and B is the same: S / V1 = (S-60) / V23, and the above 1,2 equations are established, and s
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