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A, B students from a to B, a walking speed is 3km / h, B walking speed is 5km / h, two people riding a bicycle speed is 15km / h, now a first walk, B first ride a bicycle, two people start at the same time, walk a distance, B put off to walk, a go to B place to ride a bicycle, then continue to alternate, two people just at the same time to B, find a walk the average speed Please use the equation Just tell me how to make the equation ------------------------------- By 6:00 tomorrow morning The method of solving equations
There are only two ways to walk with students a and B: cycling or walking, because it's alternating. From the statistics, the distance a rides + the distance a walks = the distance b rides + the distance b walks + the time a rides + the time a walks = the time B rides + the time B walks (arrive at the same time) the time a rides
Party A and Party B are walking towards each other, 20km / h and 18km / h. when they meet, they are 3000 meters away from the key point. How far is this road?
A is 20-18 kilometers faster than B per hour
It is 3km away from the midpoint, indicating that Jia has walked 3 * 2 = 6km more
So, the time they go is 6 / 2 = 3 hours
The sum of speed is 20 + 18 = 38 km / h
38 * 3 = 114 km
The distance of the road is 114 kilometers
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