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Party A and Party B start from two places 60 kilometers apart and walk in opposite directions at the same time. The walking speed of Party A is 5 km / h, and Party B meets each other after riding for 3 hours to find the speed of Party B. If two people walk in the same direction from two places at the same time, Party A is in the front and Party B is in the back, how many hours will it take Party B to catch up with Party A? The answer is that B's speed is 15 km / h, and it takes 6 hours for B to catch up with a Please use the equation
Let the velocity of B be x km / h
Then: 5 * 3 + 3x = 60
So x = 15
So the speed of B is 15 km / h
That's how it should be done
A and B both rode bicycles at the same time from AB, 60km away. After meeting for three hours, it is known that a's speed is 2km an hour faster than B's
How much is the bicycle speed of a and B? Solve the equation with one variable
Let B speed x km / h and a speed x + 2 km / h
Lie equation
3x＋3*（x＋2）＝60
Solution
x＝9
x＋2＝11
A and B bicycled from two places 75KM apart. They met three hours later. A walked 2km more per hour than B. how fast did a and B go
Suppose the speed of a is x km / h, then the speed of B is X-2 km / h
（X+X-2）*3=75
6X-6=75
6X=81
X=13.5
X-2=11.5
A: the speed of a and B is 13.5km/h and 11.5km/h respectively
A and B ride bicycles from two places 60km apart and meet two hours later. If a rides 2km more per hour than B, B's speed is ()
A. 13 km / H B, 14 km / H C, 15 km / H D, 16 km / h
(60 △ 2-2) △ 2 = 14 (km)
So choose B
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