At the same time, the passenger train and the train leave from a and B. when they meet, the distance ratio of the passenger train and the freight train is 5:4. After meeting, the freight train is 15 times faster than the passenger train per hour It is known that the freight car has been traveling for 10 hours. How many kilometers is the distance between Party A and Party B? If you can draw a picture, you'd better draw it,

At the same time, the passenger train and the train leave from a and B. when they meet, the distance ratio of the passenger train and the freight train is 5:4. After meeting, the freight train is 15 times faster than the passenger train per hour It is known that the freight car has been traveling for 10 hours. How many kilometers is the distance between Party A and Party B? If you can draw a picture, you'd better draw it,


As shown in the figure (see the inserted picture)
If the speed of passenger car is 5x & nbsp; km / h, the speed of freight car is 4x before meeting and 5x + 15 after meeting;
The total distance was 9y. Before the meeting, the bus drove for 5Y and the truck for 4Y
Then:
It takes the same time for the two cars to meet
y/x+4y/5x=10
5y/(5x+15)=4y/5x
The solution is y = 200 / 3
          x=12
So the distance between a and B is 9y = 600



Two passenger and freight cars leave from a and B at the same time, and they meet in three hours. At this time, the bus runs 60% of the whole journey. It is known that the bus runs 72 meters more than the truck, so the distance between a and B is calculated


72/(60%-40%)=360



The two passenger and freight cars leave from a and B at the same time. After two hours of meeting, the freight car runs 20 kilometers more than the passenger car. It is known that the distance ratio of the two passenger and freight cars is
4: 5. How many meters are there between a and B


20 × 2 ÷ (5-4) × (5 + 4) = 360 km
I wish you progress in your study!
If you have any questions, please ask. If you understand, please adopt them in time! (*^__ ^*)