A. B is 875 kilometers away from the two cities. A and B leave each other at the same time. A runs 90 kilometers per hour. After 5 hours, the two cars meet. B runs 90 kilometers per hour How many kilometers to drive? Use the equation and tell me before 18:30,

A. B is 875 kilometers away from the two cities. A and B leave each other at the same time. A runs 90 kilometers per hour. After 5 hours, the two cars meet. B runs 90 kilometers per hour How many kilometers to drive? Use the equation and tell me before 18:30,


If vehicle B travels x kilometers per hour, then
5×(90+x)=875
x+90=175
x=85
Car B runs 85 kilometers per hour



Two cars a and B leave 875km away from each other at the same time. After 7 hours, they meet. It is known that the speed ratio of a and B is 12:13. So, we can find the speed ratio of a and B
B what's the speed of the two cars?


Hello
Speed sum of two cars = 875 △ 7 = 125 (km)
The speed of car a = 125 ÷ (12 + 13) × 12 = 60 (km)
Vehicle B speed = 125-60 = 65 (km)



Xiao Wang drives from city a to city B, 45 kilometers per hour, and arrives in 4 hours. When he comes back, the speed increases by 20%. How long does it take to get back?


Xiao Wang drives from city a to city B, 45 kilometers per hour, and arrives in 4 hours
Then the distance between AB is d = 45 × 4 = 180 (km)
It's 20 percent faster when it comes back,
Then the speed of returning is v = 45 (1 + 20%) = 54 km / h
So the return time t = D / v = 180 / 54 = 10 / 3 hours
I hope I can help you. If you have any questions, please ask,