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The distance between the two stations is 1086km, and the speed ratio of a and B trains is 3:4 when they meet after 6:00 from the two stations,
1086 / 6 * 3 / (3 + 4) = 77.57km/h
1086 / 6 * 4 / (3 + 4) = 103.43km/h
The distance between a and B is 900km. A train departs from a to B at 7:30 in the morning. It stops at several stations on the way and arrives at B at 16:30 on the same day. The train passes the 400m long bridge at a speed of 144km / h, and the time for the train to pass the bridge is 25s
(1) What's the average speed of the train from place a to place B?
(2) What's the length of the train?
(1) The total driving time is 16.5 - 7.5 = 9 hours and the average speed is 900 △ 9 = 100km / h
(2) 144km / h × 25s = 40m / s × 25s = 1000m, train length 1000-400 = 600m
A and B go to the railway station from school at the same time. The distance between the school and the railway station is a kilometer. A rides a bicycle for B hours. B rides a bicycle 20 minutes earlier than A. go to the railway station and ask a and B the speed ratio
20 minutes = 1 / 3 hour
Velocity of a = A / b
Velocity of B = A / (B-1 / 3)
A / b speed ratio = (B-1 / 3): B
The passenger and freight trains start from the East and West stations at the same time. The passenger trains run 56 kilometers per hour and the freight trains 48 kilometers per hour. The two trains meet 40 kilometers away from the two stations
How many kilometers is the distance between the East and West stations?
In every step of solving the equation, we have to explain why we calculate the equation in this way
The distance between two stations is x km
Meeting time: X / (56 + 48)
Equivalent relationship: the distance difference between passenger car and freight car is 40 × 2km when they meet
（56-48)*x/(56+48)=40×2
8x/104=80
x=80÷8×104
x=1040
A: the distance between the two stations is 1040 km
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