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The speed of a is 90 km / h, and that of B is 60 km / h. on the way, a is delayed for 2 hours, and the result is that a is leaving The two cars meet at the midpoint of 12 kilometers, seeking the distance between a and B
There are two situations: the first one is that they meet on the side closer to a's starting place
Set the distance as X and the time as y
Then 90 (Y-2) = x / 2-12
60Y=X/2+12
The solution of the equations is x = 600 km
Second, they meet on the side closer to the starting point of B
Then 90 (Y-2) = x / 2 + 12
60Y=X/2-12
The solution is x = 840 km
a. The distance between B and B is 90km, and a and B vehicles run from a and B at the same time. Car a travels 60 km per hour, and the speed of car B is four fifths of that of car A. how long does it take for the two vehicles to meet?
emergency
90÷（60+60×4/5）
=90÷（60+48）
=90÷108
=5 / 6 (hour)
=50 (points)
A car at a certain speed from city a to city B can reach 5 hours. After 3.5 hours from city a, the car is 90 kilometers away from city B. how many kilometers are there between city a and city B?
[90 ÷ (5-3.5)] × 5 = 60 × 5, = 300 km. A: the distance between city a and city B is 300 km
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