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The distance between the two places is 200km. The speed of a is 20km / h, and the speed of B is 30km / h. A starts for one hour, and after a few hours, the two people are 30km apart
A walked 20 * 1 = 20 km in an hour
It is also 200-20 km away
Time needed (180-30) / (20 + 30) = 3 hours
Or 210 / (20 + 30) = 4.2 hours
The distance between station a and station B is 200 km. Car a starts from station a and travels 20 km per hour. Car B starts from station B and travels 30 km per hour
(1) The express train goes ahead for 30 minutes, and the two trains are facing each other. How many hours has the local train been running?
(2) The two cars leave at the same time and go in the same direction. How many hours later will car B catch up with car a?
(1)(200-30×30÷60)÷(20+30)
=185÷50
=3.7 (hours)
(2)200÷(30-20)
=200÷10
=20 (hours)
The distance between car a and car B is 200km, car a travels 50km per hour, car B travels 30km per hour. After a few hours, the distance between car a and car B is 30km?
There are two solutions to this problem
Not met: (200-30) / (50 + 30) = 2.125 hours
Met: (200 + 30) / (50 + 30) = 2.875 hours
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