The length of the fast and slow trains are 150 meters and 200 meters respectively. They run on parallel tracks in opposite directions. If people on the slow train see the fast train passing the window, the time is 6 minutes Second, how many seconds does it take for people on the express to see the local train passing the window? Why?

The length of the fast and slow trains are 150 meters and 200 meters respectively. They run on parallel tracks in opposite directions. If people on the slow train see the fast train passing the window, the time is 6 minutes Second, how many seconds does it take for people on the express to see the local train passing the window? Why?


First of all, find the relative speed of the two trains. If the slow train looks at the fast train for 6 seconds, set the slow train to be stationary. Then the relative speed = the length of the fast train / 6 = 150 / 6 = 25m / s
Then the express driver looks at the slow train, and sets the fast train to be stationary, and the relative speed is still 25m / s, then the time = slow train length / relative speed = 200 / 25 = 8 seconds



An express train is 160 meters long and a local train is 170 meters long. If the two trains are running in opposite directions, it will take 5 seconds for them to run into each other and leave. If the two trains are running in opposite directions, they will catch up with each other
It takes 33 seconds for the slow train to leave the slow train completely. Find the speed of the fast train and the slow train


Assuming that the fast train speed is x m / s and the slow train speed is Y M / s, then: 33x-33y = 160 + 170; 5x + 5Y = 160 + 170; solving the equation can get: x = 38, y = 28



An express train is 306 meters long, and a slow train is 344 meters long. The two trains are facing each other, and it takes 13 seconds from meeting to leaving. If a car leads to it, the express train will catch up with the slow train


Go in opposite directions
(fast train length + slow train length) / (fast train speed + slow train speed) = 13 seconds
Go in the same direction
(fast train length + slow train length) / (fast train speed - slow train speed) = required time



An express train and a local train run in opposite directions. The length of the express train is 280 meters, and that of the local train is 385 meters. The time for people sitting on the express train to see the local train passing is 11 seconds, so the time for people sitting on the local train to see the express train passing is 11 seconds______ Seconds


The relative speed of the two trains is: 385 △ 11 = 35 (M / s); the time for people on the slow train to see the fast train passing is: 280 △ 35 = 8 (s)