Given that the reciprocal sum of three natural numbers is 47 / 60, find the three numbers

Given that the reciprocal sum of three natural numbers is 47 / 60, find the three numbers


60=3×4×5
3×4 + 3×5 + 4×5 = 12 + 15 + 20 = 47
The reciprocal sum of 3, 4 and 5
= 1/3 + 1/4 + 1/5
= 4×5/60 + 3×5/60 + 3×4/60
= 47/60



Which natural number is 34 out of 1995?
I'm in a hurry


It is true that there is no ~ if there must be, it can only be rounded to 57~



Which four natural numbers add up to 34 / 1995?


∵1995=3×5×7×19
And 3 + 5 + 7 + 19 = 34
The four numbers are: 1995 / 3; 1995 / 5; 1995 / 7; 1995 / 19
That is, the four numbers are 665; 399; 285; 105