The sum of the reciprocal of several continuous natural numbers is 47 / 60. How many are these natural numbers? Please write down the process in detail, I will thank you very much My child's sixth grade problem

The sum of the reciprocal of several continuous natural numbers is 47 / 60. How many are these natural numbers? Please write down the process in detail, I will thank you very much My child's sixth grade problem


Because the denominator is 60, the continuous natural number should be 3 4 5
After multiplying the three numbers, the denominator 3 * 4 * 5 = 60 is ensured



The sum of the reciprocal of several continuous natural numbers is 57 out of 60. What are these natural numbers


The prime factor of 60 is as follows:
60=2*2*3*5=3*4*5
And because: 3 * 5 + 4 * 5 + 3 * 4 = 57
So:
These natural numbers are: 3,4,5



The sum of the reciprocal of several consecutive natural numbers is 47 out of 60. What are these natural numbers


3.4.5



The reciprocal sum of several continuous natural ripening is 47 / 60. What are these natural numbers


60=3×4×5
3×4+3×5+4×5=47
These natural numbers are 3, 4 and 5