A cuboid with a square bottom becomes a cube when its height is shortened by 5 cm, and its surface area is reduced by 240 square cm Find the surface area of the original cuboid

A cuboid with a square bottom becomes a cube when its height is shortened by 5 cm, and its surface area is reduced by 240 square cm Find the surface area of the original cuboid

Cube side length = 240 △ 4 △ 5 = 12 cm
H = 12 + 5 = 17 cm
Original surface area = 6 × 12 × 12 + 240 = 1104cm2

After the edge length of a square is shortened by half, the surface area of the small square is 72 square centimeters less than that of the original square. What is the surface area of the original square

Let the length of the original square be X. then the length of the shortened square is x / 2
6*x^2/4=6x^2-72
3x^2/4=12
x^2=16
X = 4
So the original surface area of the square is: 4 * 4 * 6 = 96

A cuboid with a square bottom becomes a cube after its height is shortened by 5 cm, and its surface area is reduced by 120 square cm

Square side length = 120 △ 5 △ 4 = 6cm
Original length = width = 6cm
H = 6 + 5 = 11cm
Original area = 2 * (6 * 6 + 6 * 11 + 6 * 11) = 336 square centimeters