Given that the lengths of two sides of a right triangle are 6 and 10 respectively, the length of the third side is______ .

Given that the lengths of two sides of a right triangle are 6 and 10 respectively, the length of the third side is______ .


Let the length of the third side be a, when a is a hypotenuse, a = 62 + 102 = 234; when 10 is a hypotenuse, 10 = 62 + A2, the solution is a = 8



If both sides of a right triangle are 6 and 8 long, then the area of the triangle is______ .


When 6 and 8 are two right angle sides, the area of triangle is 12 × 6 × 8 = 24. When 8 is a hypotenuse, let another right angle side be H. according to Pythagorean theorem, H = 82 − 62 = 27, the area of triangle is 12 × 6 × 27 = 67. So the answer is: 24 or 67



It is known that the area of parallelogram is 90 square centimeter, ed = 1 / 3 AD.BF=3/5 BC, OD = 2 / 5 BD, how many square centimeters is the shadow area?
Shadow: BFO, Edo
It's mainly about "BFO"!


Connect the auxiliary lines OA and OC according to the contour principle,
The area of triangle OED = 1 / 3 of oad area = 1 / 3 * 2 / 5 of oad area;
Similarly, the area of oBf = 3 / 5 OCB = 3 / 5 * 3 / 5 BOC
Add the equations and bring in the quadrilateral area to get the shadow area



In rectangle ABCD, BD is diagonal, AE is perpendicular to BD, BC and e intersect, area of triangle AOB is 54, OD = 16, OB = 9, calculate area of quadrilateral OECD (upper left corner is a, lower left corner is B, upper right corner is D, lower right corner is C; O is intersection point of AE and BD)
Leave the formula!


119.625



The three sides of a right triangle are 3cm, 4cm and 5cm respectively. How many square centimeters is the area of this right triangle


By using the Pythagorean theorem, the sum of the squares of the lengths of the two right angles of a right triangle is the square of the length of the oblique side. It is known that it is a right triangle, then it must be 3 & # 178; + 4 & # 178; = 5 & # 178;, otherwise it does not satisfy the Pythagorean theorem, so 3 and 4 are right angles, s = 3 × 4 △ 2 = 6



An isosceles right triangle, its area is 72 square decimeters, the length of his two right sides are () band analysis


12 decimeters
Using the area formula of isosceles right triangle s = 1 / 2A ^ 2, s is 72, and substituting it into the solution, a = 12 decimeters



The three sides of a right triangle are 3cm, 4cm and 5cm long respectively. They rotate around the three sides to form three geometric bodies. Imagine and tell the structure of the three geometric bodies, draw their three views, and calculate their surface area and volume


Taking the rotation around 5cm edge as an example, the direct view, front (side) view and top view are as follows: (2 points) the surface is two fan-shaped, so the surface area is s = 12.2 π· 125 · (3 + 4) = 845 π (cm2); (3 points) the volume is v = 13 π· (125) 2.5 = 485 π (cm3); (4 points) similarly, it can be obtained that when rotating around 3cm edge, s = 36 π (cm2), v = 16 π (cm3); (8 points) The front (side) view and top view are: the front (side) view and top view are: S = 24 π (cm2), v = 12 π (cm3) when rotating around 4cm edge



The length of one right side of a right triangle is 5cm, and the length of the other right side is 1cm shorter than the hypotenuse


Let the hypotenuse be x, then the other right angle is X-1
Square of (x-1) + square of 5 = square of X
The bevel x = 13



If the hypotenuse of a right triangle is 5cm long and one right side is 1cm longer than the other right side, the area of the right triangle is______ cm2.


Let the length of the shorter right angle side be xcm, then the length of the other right angle side be: (x + 1) cm. From the Pythagorean theorem, it is obtained that x2 + (x + 1) 2 = 52. From the solution, x = 3, then x + 1 = 4. The area of this right triangle is 12 × 3 × 4 = 6cm2. So the answer is: 6



It is known that the area of a square is equal to that of a right triangle, and the two right sides of the right triangle are 5 cm and 6 cm respectively


From the known area of right triangle = (1 / 2) * 5 * 6 = 15
Then the square area = side length & # 178; = 15
Side length = root 15