The axis of symmetry of the parabola y = (K & sup2; - 2) x & sup2; + m-4kx is a straight line x = 2, and its lowest point is in the straight line y = - 0.5x+ The axis of symmetry of parabola y = (K & sup2; - 2) x & sup2; + m-4kx is a straight line x = 2, and its lowest point is on the straight line y = - 0.5x + 2

The axis of symmetry of the parabola y = (K & sup2; - 2) x & sup2; + m-4kx is a straight line x = 2, and its lowest point is in the straight line y = - 0.5x+ The axis of symmetry of parabola y = (K & sup2; - 2) x & sup2; + m-4kx is a straight line x = 2, and its lowest point is on the straight line y = - 0.5x + 2


From the symmetry axis X = 2, x = - B / 2A = 4K / 2 (k ^ 2-2) = 2,
k^2-k-2=0,
k1=-1,k2=2,
Because K ^ 2-2 is not 0, k = - 1
Substituting x = 2 into y = - 0.5x + 2, y = 1, vertex coordinates (2,1)
In the function, M = - 3
So: y = - x ^ 2 + 4x-3



It is known that the axis of symmetry of the parabola y = 5x + BX + C is x = - 2, and the minimum value is 7. Find the analytic expression of the function and the values of B and C


Y = 5x ^ 2 + BX + C = 5 (x ^ 2 + BX / 5) + C = 5 (x ^ 2 + BX / 5 + B ^ 2 / 100) + C - B ^ 2 / 20 = 5 (x + B / 10) ^ 2 + C-B ^ 2 / 20 because the axis of symmetry is x = - 2, so x = - B / 10 = - 2b = 20, because the minimum value is 7, then C-B ^ 2 / 20 = C-20 = 7C = 27, so the analytical formula is y = 5x ^ 2 + 20x + 27



If the axis of symmetry of a parabola is x = 1 and has a unique common point with X axis, and the opening direction is downward, then the analytical formula of the parabola is______ Write any one


Let the quadratic function y = AX2 + BX + C, the ∵ axis of symmetry be x = 1 and have a unique common point with X axis, and the opening direction is downward, ∵ a < 0, B = - 2A, △ = 0, that is, b2-4ac = 0. For example, y = - x2 + 2x-1