The reasoning process of calculating the radius of inscribed circle and circumscribed circle of triangle RT
Given that the side lengths of three vertices a, B and C of △ ABC are a, B and C in turn, the area s of △ ABC is s = √ [(a + B + C) (- A + B + C) (a-b + C) (a + B-C)] / 4 according to Helen's formula; if the radius of the inscribed circle of △ ABC is R and the radius of the circumscribed circle is r, then: ∵ s = (AR / 2) + (BR / 2) + (CR / 2), ∧ r = 2S / (a + B + C), that is, r = √ [(...)
The formula of circumscribed circle radius and inscribed circle radius of arbitrary triangle
That's a point
2R=A/SINA=B/SINB=C/SINC
Should be