What is the nature of the height on the hypotenuse of a right triangle All in all, I am a junior high school student. So I need junior high school knowledge

What is the nature of the height on the hypotenuse of a right triangle All in all, I am a junior high school student. So I need junior high school knowledge

As for the height, first, it is perpendicular to the bottom edge; then, the product of the low times the height equals to the product of two right angles; and then, it is just like the right triangle ABC, where CD is the height of the hypotenuse, and the square of CD equals ad * CD

Verification: the sum of the diameter of the inscribed circle and the diameter of the circumscribed circle of a right triangle is equal to the sum of the two right angles

Let ABC be a right triangle,

Proof: the radius of the inscribed circle of a right triangle is equal to half of the difference between the sum of two right angles and the hypotenuse

Let ∈ C = 90 °, ab = C, BC = a, AC = B in △ ABC. His inscribed circle O is tangent to AB, BC, AC at points F, D, e respectively, and its radius is R. connecting od and OE, we prove that odcf is a square (omitted), so EC = DC = R, so BD = A-R, AE = B-R, and BD = BF, AE = AF, so BF = A-R, AF = B-R, so C = BF + AF