1. Evaluate 25 ^ log (5) ^ 3 + LG100 + log (1 / 2) 4 The value of 2.9 ^ log (3) ^ 5 is () A.5 B.15 C.25 D.45 3. Calculate log (2) 2 + log (5) 1-log (1 / 3) 1 / 27 + [3 ^ log (3) 5] ^ 2 + 3 ^ log (3) 2

1. Evaluate 25 ^ log (5) ^ 3 + LG100 + log (1 / 2) 4 The value of 2.9 ^ log (3) ^ 5 is () A.5 B.15 C.25 D.45 3. Calculate log (2) 2 + log (5) 1-log (1 / 3) 1 / 27 + [3 ^ log (3) 5] ^ 2 + 3 ^ log (3) 2


one point nine
two point two five
three point two five



1. If x + y = - 6, xy = 2.75, then X-Y =?
2. If X & sup2; + MX-15 = (x + 3) (x + n), what is the value of M?
3. What is the value of (2 + 1) (2 & sup2; + 1) (2 ^ 4 + 1). (2 ^ 2n)?


1.(x+y)^2=36
x^2+y^2+2xy=36
x^2+y^2=36-2*2.75=30.5
(x-y)^2=x^2+y^2-2xy=30.5-2*2.75=25
X-Y = 5 or - 5
2.m=-2
n=-5
3.(2+1)(2^2+1)(2^4+1).(2^2n+1)
=(2-1)(2+1)(2^2+1)(2^4+1).(2^2n+1)
=2^4n-1



1. The average number of a, B and C is 150. The number of a is 48. The number of C is twice that of B. find the number of B. 2. Liu Mei reads a book, 248 pages in the first eight days, and the rest is ready to read in nine days. If the book has 590 pages, how many pages must be read in the next nine days? 3. The fifth grade students participate in afforestation activities, How many trees per person in grade five?


1、
(150x3-48)÷3
=(450-48)÷3
=402÷3
=134
2、
(590-248)÷9
=342÷9
=38
3、
(42x6+45x5)÷(42+45)
=(252+225)÷87
=477÷87
≈5.4



The distance between the two places is 90km. The distance on the map is 3cm. The scale of this map is ()
A machine part is 12 meters long. On the design drawing, the part is 8 cm long. The scale of this design drawing is ()
On a map with a scale of 1:500, the distance between a and B is 9cm, and the actual distance between the two places is ()


"Yue cake love Yue Yingying" Hello, I'm glad to answer for you!
The distance between the two places is 90km. The distance on the map is 3cm. The scale of this map is (1:3000000)
3cm: 90km = 3cm: 9000000cm = 1:3000000cm
A machine part is 12 meters long. On the design drawing, the part is 8 cm long. The scale of this design drawing is (1:150)
8cm:12m=8cm:1200cm=1:150
On a 1:500 scale map, the distance between a and B is 9 cm, and the actual distance between the two places is (45 meters)
9 × 500 = 4500 (CM) = 45 (m)
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