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When doing division without remainder, we know that the divisor + divisor x quotient = 60, what is the divisor?
thirty
In division without remainder, the divisor + quotient x divisor = 48, what is the divisor equal to?
Why is the divisor 2
Divisor = quotient x divisor
So division = 48 / 2 = 24
In division without remainder, the divisor + divisor × quotient = 174, the divisor is______ ．
Because the divisor = divisor × quotient, so the divisor is 174 △ 2 = 87, so the answer is: 87
Ask for some questions about the first integral of junior high school to get rid of the brackets. Because I'm required to finish the preview, I'm sorry, so I'm here to consult you. Make sure it's correct
1、 Remove the brackets from the following integers
-（-a-b)
5x-(2x-1)-xˆ2
3xy-0.5(xy-yˆ2)
(aˆ3+bˆ3)-3(2aˆ3-3bˆ3)
2、 First remove the brackets, then merge the similar items
a+(-3b-2a)
(x+2y)-(-2x-y)
6m-3(-m+2n)
aˆ2+2(a ˆ2-a)-4(aˆ2-3a)
3、 Remove the brackets before calculating
(5a+b)+6a
5-(7-6m)
(2x-7)-(4x-5)
4、 Remove the brackets before calculating
(3aˆ2-3a-1)-(5aˆ2+6a-8)
(8mn-3mˆ2)-5mn-2(3mn-2mˆ2)
5、 First remove the brackets, then simplify, and then evaluate
3Y & # 710; 2-x & # 710; 2 + (2x-y) - (X & # 710; 2 + 3Y & # 710; 2), where x = 1, y = 2
1、 Remove the brackets from the following integers
-（-a-b)=a+b
5x-(2x-1)-xˆ2=5x-2x+1-xˆ2=3x+1-xˆ2
3xy-0.5(xy-yˆ2)=3xy-0.5xy+0.5yˆ2
(aˆ3+bˆ3)-3(2aˆ3-3bˆ3)=aˆ3+bˆ3-6aˆ3+9bˆ3=-5aˆ3+10bˆ3
2、 First remove the brackets, then merge the similar items
a+(-3b-2a)=a-3b-2a=-a-3b
(x+2y)-(-2x-y)=x+2y+2x+y=3x+3y
6m-3(-m+2n)=6m+3m-6n=9m-6n
aˆ2+2(a ˆ2-a)-4(aˆ2-3a)=aˆ2+2a ˆ2-2a-4aˆ2+12a=-aˆ2+10a
3、 Remove the brackets before calculating
(5a+b)+6a=11a+b
5-(7-6m)=6m-2
(2x-7)-(4x-5)=-2x-2
4、 Remove the brackets before calculating
(3aˆ2-3a-1)-(5aˆ2+6a-8)=-2aˆ2-9a+7
(8mn-3mˆ2)-5mn-2(3mn-2mˆ2)=-3mn+mˆ2
5、 First remove the brackets, then simplify, and then evaluate
3Y & # 710; 2-x & # 710; 2 + (2x-y) - (X & # 710; 2 + 3Y & # 710; 2), where x = 1, y = 2
3yˆ2-xˆ2+(2x-y)-(xˆ2+3yˆ2)=3yˆ2-xˆ2+2x-y-xˆ2-3yˆ2=2x-y=1-2=-1
The second unit of junior high school mathematics paper is a little more difficult about the brackets
Hungry, I want to correct the answer. Mao 0702 what you said is easy to make mistakes, others can't understand it
1. There is a "+" sign in front of the bracket. Remove the bracket and the "+" sign in front of it, and the symbols of each item in the bracket will not change
2. Before the bracket is the sign of "'", remove the bracket and the sign of "'", and change the sign of each item in the bracket to the opposite sign
(7y-3z)-(8y-5z)
-(a5-6b) - (- 7 + 3b) (a followed by square)
2 (2A2 + 9b) + 3 (- 5a2-4b) (2a, 5A followed by square)
-3 (2x2 XY) + 4 (x2 + xy-6) (2x, X followed by square)
Go to the brackets to see the symbol in front of the brackets
Before the bracket is a positive sign. Remove the bracket and the symbol before the bracket. Each item in the bracket does not change the symbol
Before the bracket is a minus sign. Remove the bracket and the symbol before the bracket. Every item in the bracket changes the symbol
Children should be good at using their brains~
Some hope you can tell me
The answers on page 15-17 of the first volume of the second grade of junior high school
I have no choice but to answer... I don't want to copy... But we will have class tomorrow. I haven't written yet. Please help me
I'll send it to you
Answers to the self-test questions in Chapter 7 of mathematics sesame blossom
1、 Cbdccdbaa II-3 / 2,3, n-2, N + 2,3n, 11,3x & sup2; + 3x-8, AB AC + bc-c & sup2;, 2a-1,4 three simple calculation problem 4 21: original formula = A-1 / 2B ∵ 2a-b = 6 ∥ original formula = (2a-b) × 1 / 2 = 322: (1) 81 * 89 = 8 * (8 + 1) * 100 + 1 * 9 = 7209 (2) original formula = 100 * n * 9 (n + 1) + AB (3) organize language by oneself
Question 12 on Page 103 of Mathematics
There must be process and reason to solve the equation
There are two shepherd boys a and B, a said to B: give me one of your sheep, and my sheep number is twice of yours. B: give me one of your sheep and we'll have the same number of sheep. How many sheep do the two shepherd boys have?
Let a have X and B have y, then
2（y-1）=x+1
x-1=y+1
We get x = 7, y = 5
There are seven in a and five in B
or
Let a have X, then B have (x + 1) / 2 and one more
X-1 = (x + 1) / 2 plus 1 plus 1
The solution is x = 7, y = 5
There are seven in a and five in B
RELATED INFORMATIONS
- 1. In a division formula without remainder, the sum of divisor and divisor is 200, the quotient is 4, what is the divisor?
- 2. In division without remainder, the divisor is divided by ten and the divisor is divided by two?
- 3. In a division formula without remainder, the sum of the divisor, divisor and quotient is 200, and the quotient is 2
- 4. In a division without remainder, if the divisor and quotient are equal, what is the divisor?
- 5. Use a simple method to calculate the following questions, and check them. 580 ／ 20 760 ／ 60 1000 ／ 300
- 6. (9x-9) △ 3 = 5.4 (checking calculation) to solve the equation
- 7. Calculation: minus one and three-thirds plus two and two-thirds minus three and three-thirds plus four and two-thirds Minus 5 and 1 / 3 to add 1992 and 1 / 2
- 8. 73.3-4.46 = (calculated and checked)
- 9. 1. Let f (1-x / 1 + x) = x, then the expression of F (x) is: 2. Given the quadratic function f (x) = x2 + X + a (a > 0), if f (m)
- 10. 1. Evaluate 25 ^ log (5) ^ 3 + LG100 + log (1 / 2) 4 The value of 2.9 ^ log (3) ^ 5 is () A.5 B.15 C.25 D.45 3. Calculate log (2) 2 + log (5) 1-log (1 / 3) 1 / 27 + [3 ^ log (3) 5] ^ 2 + 3 ^ log (3) 2
- 11. When Wang Ming calculates the division with remainder, he takes the divisor 125 as 152. The quotient of the result is three times larger than the correct result, but the remainder is exactly the same
- 12. When calculating the division with remainder, 308 is wrongly written as 368, and the quotient is increased by 5 and the remainder is just right
- 13. Xiao Ming is calculating the division with remainder. He mistakenly writes 308 as 368, and the quotient increases by 5, but the remainder is exactly the same. So he can find the divisor and remainder of the formula
- 14. In the division formula without remainder, the divisor divisor × quotient = () A. Divisor B. 0C. Quotient D. dividend
- 15. In division with remainder, the divisor is equal to several times several plus several
- 16. When Xiao Ming calculates the division with remainder, he wrongly writes the divisor 115 as 151, and the result quotient is 3 larger than the correct result, but the remainder is exactly the same______ ．
- 17. When Xiao Zhang calculates the division with remainder, he takes the divisor 113 as 131, and the result quotient is 3 more than the original, but the remainder is exactly the same, so the remainder of the problem is () A. 、4B. 5C. 6D. 7
- 18. In the division operation with remainder, the divisor is equal to the product of divisor and quotient, plus (). What number should be filled in the brackets below to make the divisor maximum （）÷9=8…… （）
- 19. Subtraction is the inverse of addition, and division is the inverse of multiplication______ ．
- 20. How to check the addition and subtraction method