If there are four mutually unequal integers a, B, C, D and ABCD = 9, then a + B + C + D equals () A. 0b. 8C. 4D. Not sure

If there are four mutually unequal integers a, B, C, D and ABCD = 9, then a + B + C + D equals () A. 0b. 8C. 4D. Not sure

The four numbers are less than or equal to 9, and they are not equal to each other. From the product of 9, there must be 3 and - 3 in the four numbers. The four numbers are: 1, - 1, 3, - 3, and the sum is 0

Given that the product of four integers ABCD is equal to nine, and a < B < C < D, find the value of AB + CD
Can you add a Q

9=(-9)×(-1)
=(-3)×3×(-1)×1
a＜b＜c＜d
a=-9,b=-1,c=1,d=9
So the original formula = (- 9) × (- 1) + 1 × 9
=9+9
=18
I use Baidu Hi

Given the product of four integers ABCD = 25, a < B < C < D, find the value of AB + CD

A = - 5, B = - 1, C = 1, d = 5
So AB + CD = 10

We know that the product of four integers ABCD = 25, and a

25=5*5=-1*5*-5*-1 a=-5 b=-1 c=1 d=5 ab=5 cd=5 ab+cd=10

It is known that ABCD is four mutually unequal integers, and their product ABCD = 9

Possible values of a B C 1 3 9
A = 1, B = 1, C = 1, d = 9, the result is one in nine;
B = 1, C = 1, d = 1, a = 9, the result is 9;
A = 3, C = 3, B = 1, d = 1, the result is 1;
So there are three numbers in the result; I list a few cases, but the result can only be these three cases!

If we know the product of four numbers ABCD = 25 and a is greater than B and C is greater than D, we can find the value of AB + CD

There are many answers
ABCD = 25 and a is greater than B, C is greater than D
Let a = 3, B = 5 / 2, C = 2, d = 5 / 3
ab+cd=15/2+10/3=65/6

Given four mutually unequal integers ABCD, their product is 25, find the value of a + B + C + D
Seeking process!!!!!!!

(-1) × 1 × (-5) × 5 = 25
- 1 + 1 - 5 + 5 = 0

There are four unequal integers whose product ABCD = 9. What is the value of a + B + C + D
Because of that, I also said
Because so also said! Because so also said!

Because ABCD is an integer
So according to 9 = 1 * 9 = 1 * 3 * 3
1 = 1 * 1 or - 1 * - 1
3 = 1 * 3 or - 1 * - 3
So 9 = - 1 * - 3 * 1 * 3
Then a + B + C + D = - 1 + 1-3 + 3 = 0

Four unequal integers a.b.c.d. their product ABCD = 9, then what is the value of a + B + C + D

Because 9 = 3 * 3
So ABCD can only take 1, - 1,3, - 3
Then a + B + C + D = - 1 + 1-3 + 3 = 0

If the edge length of the triangular prism is 2, the bottom surface is an equilateral triangle with side length of 2, Aa1 ⊥ surface a1b1c1, and the front view is a square with side length of 2, the area of the left view is
∵ the base of the triangular prism is an equilateral triangle with a side length of 2,
After the height of the equilateral triangle is made, a right triangle is formed, and the half of the bottom edge is 1,
The height of an equilateral triangle is 3,
The left view is a rectangle with height of 2 and width of √ 3,
The area of the left view is 2 ×√ 3 = 2 √ 3,
How can I see that the side view of prism should be a square with side length of 2? How can I see that the left view is a rectangle with height of 2 and width of √ 3

Imagine compressing the triangular prism from the left to the middle, and the rest of the figure is the left view from the left. The width is the height of the original equilateral triangle - that is, the left view is a rectangle with a height of 2 and a width of √ 3