As shown in the figure, there is a plastic rectangular template ABCD, which is 10cm long and 4cm wide. Place the right angle vertex P of PHF on the edge of AD (not coincident with a and D), and move the vertex P properly on ad. (1) can you make the two right angle edges of your triangle pass through point B and point C respectively? If you can, please find out the length of AP at this time; if you can't, please explain the reason; (2) move the position of the triangle plate again, so that the vertex P of the triangle plate moves on ad, the right angle side pH always passes through point B, the other straight angle side PF and DC extension line intersect at point Q, and BC intersect at point E, can you make CE = 2 & nbsp; cm? If you can, please find out the length of AP; if not, please explain the reason

As shown in the figure, there is a plastic rectangular template ABCD, which is 10cm long and 4cm wide. Place the right angle vertex P of PHF on the edge of AD (not coincident with a and D), and move the vertex P properly on ad. (1) can you make the two right angle edges of your triangle pass through point B and point C respectively? If you can, please find out the length of AP at this time; if you can't, please explain the reason; (2) move the position of the triangle plate again, so that the vertex P of the triangle plate moves on ad, the right angle side pH always passes through point B, the other straight angle side PF and DC extension line intersect at point Q, and BC intersect at point E, can you make CE = 2 & nbsp; cm? If you can, please find out the length of AP; if not, please explain the reason

(1) Let AP = xcm, then PD = (10-x) cm, because ∠ a = ∠ d = 90 ° and ∠ BPC = 90 °, so ∠ DPC = ∠ ABP, so △ ABP ∽ DPC, then ABPD = APDC, that is, ab · DC = PD · AP, so 4 × 4 = x (10-x), that is, x2-10x + 16 = 0, the solution is X1 = 2, X2 = 8, so that the triangular plate can have two right angles

As shown in the figure, several points are marked on the number axis, and each adjacent point is a unit length apart. The corresponding numbers of points a, B, C and D are numbers a, B, C and D respectively, and d-2a = 10. Then the origin of the number axis should be ()
A. Point ab. point BC. Point CD. Point d

If the origin is a, then a = 0, d = 7, then d-2a = 7, which is not consistent with the known, it is excluded; if the origin is B, then a = - 3, d = 4, then d-2a = 10, which is consistent with the known, it is correct. So select B. method 2: let the number of point a be a, and the number of point d be a + 7d-2a = 10, which is transformed into a + 7-2a = 10, and the solution is a = - 3, and then observe the coordinates, we can know that the origin is point B, and select B

There are several points on the number axis, and the distance between each two adjacent points is one unit long. The four positions of the points corresponding to the rational number ABCD are shown in the figure
Compare the size of a + B and B + C

Less than

What are the specific steps of drawing the process flow chart of sewage treatment plant with CAD? Do you first draw each construction process and then connect them,
Do you want to pay attention to the elevation and so on? I see the flow chart on the Internet. All the structures are not in a horizontal line or vertical line. I hope you CAD experts can teach me how to layout. I'm not very grateful

The process flow chart is another way to express the process. It is different from the piping diagram. It does not need to express the size and position of the equipment as the original equipment. But in order to make the layout uniform, we also need to make a certain proportion, such as equipment and equipment

In order to improve the production and living environment of urban and rural people, our city has invested a lot of money to control the pollution of Zhupi river. A comprehensive sewage treatment plant has been set up in the suburb of the city. There is a ton of sewage to be treated in the reservoir, and the sewage flowing into the reservoir from the urban area is increased by a fixed flow of B tons per hour. If two units are started at the same time, it takes 30 hours to treat the sewage, and four units are started at the same time, it takes 1 hour If the sewage treatment is required to be completed within 5 hours, at least how many units should be started at the same time?

If one unit is set to treat V tons of sewage per hour, at least x units need to be started to treat the sewage within 5 hours, then a + 30b = 2 × 30VA + 10B = 4 × 10va + 5B ≤ 5xv. The solution is a = 30vb = v. substituting it into x ≥ a + 5b5v = 30V + 5v5v = 7. A: to treat the sewage within 5 hours, at least 7 units need to be started at the same time

A 4 * 4 square matrix, seek the law!
3 4 8 6
1 9 4 2
2 7 3 9
X 1 6 7
What is x and what is the law?

Eight people think that 1 23 4 6 7 9 in the square array appeared twice, only 8 appeared once

It took 40 minutes for car a and 512 hours for car B to go from place a to place B. how much faster is car B than car a?

512 hours = 25 minutes, (125-140) △ 140, = 3200 △ 140, = 60%; a: the speed of car B is 60% faster than that of car a

A sewage treatment plant processes 4 / 3 tons of sewage in the first day, and 6 / 1 tons less in the second day than in the first day. How many thousand tons of sewage does this sewage treatment plant process in two days?

On the first day, 4 / 3 tons of sewage will be treated,
The second day is 1 / 6 tons less than the first day, i.e. 4 / 3 × (1-1 / 6)
Total sewage treatment in two days is 4 / 3 + 4 / 3 × (1-1 / 6) = 4 / 3 × 11 / 6
I know that the next day's 6 / 1 must be 1 / 6, but I'm not sure whether the first day is 4 / 3?
In addition, are there any errors between the last thousand tons and the first two days' tons?

As shown in the figure, in the quadrilateral ABCD, ad ∥ BC, ∠ B = 90 °, ad = 18cm, BC = 21cm, the moving point P starts from a and moves at 1cm / s along the ad side to D, the moving point Q starts from C and moves at 2cm / s along the CB side, P and Q start from points a and C at the same time, and when one point reaches the end point, the other point also stops moving. Suppose that the moving time is T seconds, what is the value of T when the quadrilateral PQCD is equal Waist trapezoid?

As shown in the figure, the crossing points D and Q are de ⊥ BC in E, QN ⊥ ad in n. ∵ a = ⊥ B = ⊥ bed = 90 °, abed is rectangular, ∵ ad = be, ∵ in right angled trapezoid ABCD, ad ∥ BC, ⊥ B = 90 °, ad = 18cm, BC = 21cm, ∵ CE = bc-be = BC-AD = 21-18 = 3cm. ∵ quadrilateral PQCD is isosceles trapezoid, ∵ PQ = DC, EC = NP = 3, the distance of Q point 2T = 18-t + 2 × 3 QCD is isosceles trapezoid

Given that a, B, C and D are four unequal integers, and ABCD = 25, how much does a + B + C + D equal?

Because the divisor of 25 is only 1,5,25, so 25 = 1 * 5 * (- 1) * (- 5), so a + B + C + D = 1 + 5-1-5 = 0