Draw the image of y = 2|x + 1| - 3|x-2|

Draw the image of y = 2|x + 1| - 3|x-2|


x ≥ 2:y = 2(x + 1) - 3(x - 2) = -x + 8
-1 ≤ x < 2:y = 2(x + 1) -3(2 - x) = 5x - 4
x < -1:y = 2(-x - 1) - 3(2 - x) = x - 8



If the image of quadratic function y = - x square + 4x + m is all below the x-axis, then the value range of M is the same


The solution of the quadratic function y = - x square + 4x + m is all below the x-axis
There is no intersection between the function image and the x-axis,
That is, Δ 0
That is 4 ^ 2-4 (- 1) m < 0
The solution is m < - 4