If the function y = (M & # 178; - 4) x M & # 178; - M is a quadratic function M & # 178; - M is in the upper left corner

If the function y = (M & # 178; - 4) x M & # 178; - M is a quadratic function M & # 178; - M is in the upper left corner

M & # 178; - M = 2, and M & # 178; - 4 ≠ 0
M & # 178; - m-2 = 0, that is, (M + 1) (m-2) = 0, so m = - 1, or M = 2
And M & # 178; ≠ 4, that is, m ≠ ± 2, so m = - 1
Hope to adopt

Given the intersection point (- 2,1) of the images of positive and negative scale functions, another intersection coordinate of them is obtained

y=k1x,y=k2/x
1=-2k1,k1=-1/2,y=-x/2
1=-k2/2,k2=-2,y=-2/x
Another intersection: (2, - 1)
Alternatively, the two figures are symmetrical about the origin and the intersection is symmetrical about the origin

1. Given the intersection point (- 2,1) of the image of positive and negative scale functions, find another intersection coordinate of them

Let the positive scale function be y = K1X and the inverse scale function be y = K2 / X
Because the images of positive and negative scale functions intersect at the point (- 2,1),
So 1 = - 2K1, 1 = - K2 / 2
k1=-1/2,k2=-2
The function is y = - X / 2, y = - 2 / X
LIANLI
-x/2=-2/x
x^2=4
X = 2 or x = - 2
y=-2/2=-1
So the other intersection is (2, - 1)