If the image of the inverse scale function is known to pass through points (a, b), then its image must also pass through (, The answer is a. (- A, - b) B. (a, - b) C. (- A, b) d. (0, 0)

If the image of the inverse scale function is known to pass through points (a, b), then its image must also pass through (, The answer is a. (- A, - b) B. (a, - b) C. (- A, b) d. (0, 0)

(A. - b)
Because it's an inverse scale function. Look at his picture. If one side of him is in one quadrant, the other side is in three quadrants. If the coordinate of one quadrant is (A.B), then the coordinate of three quadrants is (- A, - b)
I haven't touched that book for several years. It can only provide an idea

Given that points a (2,6) and B (3,4) are on the image of an inverse scale function, (1) find the analytic expression of the inverse scale function; (2) if the line y = MX intersects the line AB, find the value range of M

(1) Let the inverse proportion function be y = KX, according to the meaning of the problem: 6 = K2; ∫ k = 12. ∫ the inverse proportion function be y = 12x. (2) let P (x, y) be any point of line AB, then there are 2 ≤ x ≤ 3, 4 ≤ y ≤ 6; ∫ M = YX, ∫ 43 ≤ m ≤ 62. So the value range of M is 43 ≤ m ≤ 3

Given that the points a (0, - 6), B (- 3, 0), C (m, 2) are on the same straight line, try to find the analytic expression of the inverse proportion function of the image passing through one of the points and draw the image. (it is required to mark the necessary points, but the drawing method is not required.)

Let the analytic expression of the straight line AB be y = K1X + B. (1 min), then B = − 6 − 3k1 + B = 0 (2 min) and the solution is K1 = - 2, B = - 6. So the analytic expression of the straight line AB is y = - 2x-6. (3 min) ∵ point C (m, 2) is on the straight line y = - 2x-6, ∵ - 2m-6 = 2, ∵ M = - 4 Passing through point C (- 4, 2). Let the analytic expression of the inverse scale function passing through point C be y = k2x. Then 2 = K2 − 4, ∩ K2 = - 8. That is to say, the analytic expression of the inverse scale function passing through point C is y = - 8x. (6 points) the image is shown in the figure. (correct) (8 points)