It is known that the solution set of quadratic inequality ax ^ 2 + BX + C > 0 is {x | - 1

It is known that the solution set of quadratic inequality ax ^ 2 + BX + C > 0 is {x | - 1

The solution set of ax ^ 2 + BX + C > 0 is {x | - 10
The solution set is {x | x ∈ r}

The solution set of inequality ax & # 178; + BX + C > 0 is (- 1 / 3,2). For the coefficients a, B, C, we have the following conclusion
In fact, I want to know what information can be known through the interval. How can the positive and negative of a be obtained

If a is greater than 0, then the opening is upward, and the solution greater than 0 is not both sides of the parabola, then the solution should be written as (- ∞, 1) (3, + ∞)
If a is less than 0, then the opening is downward, the solution greater than 0 is the part near the vertex, and the solution is in the form of (1,2), so the problem a is less than 0

If inequality ax ^ 2 + BX + C

ax^2+bx+c

For the inequality ax & # 178; - BX + C > 0 of X, the solution set is (- 2,1). For the coefficients a, B, C, we have the following conclusion:
①a＞0
②b＞0
③c＞0
④a+b+c＞0
⑤a-b+c＞0
The number of the correct conclusion is____________

According to Weida's theorem, we can get: X1 + x2 = - A / b
-2+1=-a/b=-1；a/b=1;a=b
x1.x2=a/c
-2=a/c
The solution set of ax & # 178; - BX + C ＞ 0 is (- 2,1), which shows that a ＜ 0 (1) a ＞ 0 is wrong
A = B, B ＜ 0, B ＞ 0 error
∵-2=a/c;a＜0,∴c＞0
③ C > 0 is correct
④ A + B + C ＞ 0 can be changed from a = B, a / C = - 2 to 2A + (- 2A) = 0
⑤ In A-B + C > 0, a = B, a / C = - 2 can be changed into C > 0
The number of the correct conclusion is 3__ ⑤__________