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On the plural, －（i+1)^(n+1）-（1-i)^（n+1)=-2^[(n+3)÷2]cos[(n+1)π÷4] Why wait? How come? Is there such a substitution in the plural? What's the general formula? ^That index, lost a bit chaotic, sorry
For example, (I + 1) ^ n + (1-I) ^ n = [√ 2cos (π / 4) +? * sin (π / 4)] ^ n + [√ 2 (COS (- π / 4) +? * sin (- π / 4)] ^ n = [2 ^ (n / 2)] * [cos (π n / 4) +? * sin (π n / 4)] + [2 ^ (n / 2)] * [(COS (- π n / 4) +? * sin (- π n / 4)] = {2 ^ [(n + 1) / 2)]} * cos (π n / 4)
Mathematical problems about polar coordinate equation
What is the curve represented by polar coordinate equation ρ cos θ = 2Sin 2 θ? A straight line and a circle!)!
When cos θ = 0, the equation represents a straight line. Why? Sorry... I don't understand_
When cos θ = 0, θ = Π / 2 or 3 Π / 2 is a straight line perpendicular to the polar axis. When cos θ ≠ 0, P = 4sin θ, ρ × ρ = 4, ρ sin θ is replaced by rectangular coordinate x + y = 4x, i.e. (X-2) + y = 4, which takes (2,0) as the center and 2 as the radius
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