There is only one common point between the square of a parabola y = 1 / 2x + 3x + 5 / 2 and the square of a straight line y = 2x + m, so we can find the value of M

Solution y = 1 / 2x ^ 2 + 3x + 5 / 2
y=2x^2+m
There is a public electricity
So 1 / 2x ^ 2 + 3x + 5 / 2 = 2x ^ 2 + M
3x^2-6x+4m-5=0
Because there's only one common point
So B ^ 2-4ac = (- 6) ^ 2-4x3x (4m-5) = 96-48m = 0
So m = 2

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