If the square of X + the square of Y + 6x + 10Y + 34 = 0, then x + y =?

If the square of X + the square of Y + 6x + 10Y + 34 = 0, then x + y =?

The formula is: the square of (x + 3) + the square of (y + 5) = 0,
Because the square of any number is greater than or equal to 0,
So in order to make the above equation hold,
The square of (x + 3) is 0, and the square of (y + 5) is 0,
So x = - 3, y = - 5. X + y = - 8

X square - 6x + y square + 10Y + 34 = 0 find the value of x square + 3x divided by 2XY + 2Y

X square - 6x + y square + 10Y + 34 = 0
x^2-6x+y^2+10y+34=0,
x^2-6x+9+y^2+10y+25=0,
(x-3)^2+(y+5)^2=0
x-3=0,y+5=0,
x=3,y=-5
So x squared + 3x divided by 2XY + 2Y
=(x^2+3x)/(2xy+2y)
=(9+9)/(-30-10)
=18/(-40)
=-9/20

Given the square of X + the square of Y - 6x + 10Y + 34 = 0, x + y =?

x²-6x+9+y²+10y+25=0
（x-3）²+(y+5）²=0
x-3=0,x=3;y+5=0,y=-5
x+y=-2