Express the following condition with VB logic expression (1) The variable x is an even number divisible by 5 (2) The absolute value of X is greater than or equal to y and not equal to Z (3) X is a nonnegative integer less than 200 (4) One of X and Y is zero, but not both

Express the following condition with VB logic expression (1) The variable x is an even number divisible by 5 (2) The absolute value of X is greater than or equal to y and not equal to Z (3) X is a nonnegative integer less than 200 (4) One of X and Y is zero, but not both

  (x mod 5)=0 and (x mod 2)=0
 abs(x)>=y and abs(x)<>Z
x=int(x) and a>=0
(x=0 and y<>0) or( x<>0 and y=0)

The VB arithmetic expression is

What is the base? If the base you specify is e, that's right. In VB, the base of the default log function is e, which is the natural logarithm
If you want to change the base
As shown below, by dividing the natural logarithm of X by the natural logarithm of N, the logarithm of X can be calculated for any base n
Logn(x) = Log(x) / Log(n)
For example, log10 (x) = log (x) / log (10)

Write the VB expression of "one of X and Y is less than Z"

x