1) If f (x) = x square + 3xf '(2), then f' (2) =? 2) Given the function f (x) = f '(π / 4) cosx + SiNx, then the value of F (π / 4) is?

1) If f (x) = x square + 3xf '(2), then f' (2) =? 2) Given the function f (x) = f '(π / 4) cosx + SiNx, then the value of F (π / 4) is?

1)
f'(x)=2x+3f'(2)
Put x = 2 in
f'(2)=2*2+3f'(2)
f'(2)=-2
2) The same thing
f‘(x)=f’(π/4)（-sinx)+cosx
Substitute x = π / 4 into the above formula
Calculate f '(π / 4) = 1 / (√ 2 + 1)
Then substitute x = π / 4 into the original function
f(π/4)=f’(π/4)cosπ/4+sinπ/4=2

F (x) = f (2-x), when x belongs to [0,1], f (x) = x ^ 3, G (x) = | x * cosx |, how many zeros does H (x) = g (x) - f (x) have on [- 0.5,1]
The condition that f (x) is even is also missing

There are two zeros on [0,1], which are x = 0 / A, 0