The physical formulas of the second half of the semester are the theorem of kinetic energy, the law of conservation of momentum and so on,

The physical formulas of the second half of the semester are the theorem of kinetic energy, the law of conservation of momentum and so on,

25. Curvilinear motion: the trajectory of a particle is curvilinear motion; A1. In curvilinear motion, the direction of velocity changes at any time, and the direction of velocity of a particle at a certain point (or at a certain time) is the tangent direction of the curve at this point. 2. Conditions for a particle to move curvilinearly: the direction of external force on the particle is not in the direction of its motion

Try to deduce the expression of the law of conservation of momentum from Newton's law under the following simplified conditions: the system is two particles, the interaction force is a constant force, and it is not subject to other forces. It is required to move along a straight line. Explain the basis of each step in the derivation process, and the significance of each symbol in the formula and each item in the final result

Let M1 and M2 denote the mass of the two particles respectively, F1 and F2 denote the acting force on them respectively, A1 and A2 denote their acceleration respectively, L1 and L2 denote the interaction time of F1 and F2 respectively, P1 and P2 denote the initial velocity in the process of their interaction, V1 'and V2' denote the final velocity respectively; ① From the definition of acceleration, we can know: A1 = V1 ′ - v1t1, A2 = V2 ′ - v2t2 & nbsp; ② by substituting ② into ①, we can get: f1t1 = M1 (V1 ′ - V1), f2t2 = M2 (V2 ′ - V2) & nbsp; ③ by Newton's third law, we can know: F1 = - F2; & nbsp; T1 = T2 & nbsp; ④ From (3) and (1), we can get: m1v1 + m2v2 = m1v1 ′ + m2v2 ′ (3), where m1v1 and m2v2 are the initial momentum of the two particles, and m1v1 ′ and m2v2 ′ are the final momentum of the two particles. This is the expression of the law of conservation of momentum

Try to deduce the expression of the law of conservation of momentum from Newton's law under the following simplified conditions: the system is two particles, the interaction force is a constant force, and it is not subject to other forces. It is required to move along a straight line. Explain the basis of each step in the derivation process, and the significance of each symbol in the formula and each item in the final result

Let M1 and M2 denote the mass of the two particles respectively, F1 and F2 denote the acting force on them respectively, A1 and A2 denote their acceleration respectively, L1 and L2 denote the interaction time of F1 and F2 respectively, P1 and P2 denote the initial velocity in the process of their interaction, V1 'and V2' denote the final velocity respectively; ① From the definition of acceleration, we can know: A1 = V1 ′ - v1t1, A2 = V2 ′ - v2t2 & nbsp; ② by substituting ② into ①, we can get: f1t1 = M1 (V1 ′ - V1), f2t2 = M2 (V2 ′ - V2) & nbsp; ③ by Newton's third law, we can know: F1 = - F2; & nbsp; T1 = T2 & nbsp; ④ From (3) and (1), we can get: m1v1 + m2v2 = m1v1 ′ + m2v2 ′ (3), where m1v1 and m2v2 are the initial momentum of the two particles, and m1v1 ′ and m2v2 ′ are the final momentum of the two particles. This is the expression of the law of conservation of momentum