The mass of the inclined trolley is m and the height is h. When an object with mass m slides down from the top of the trolley, the speed of the object sliding away from the bottom of the inclined trolley is set as V, regardless of all friction. The following statements are: ① the speed of the object sliding away from the trolley v = 2GH; ② the speed of the object sliding away from the trolley V < 2GH; ③ the speed of the object sliding away from the trolley v = MVM; ④ the speed of the object sliding away from the trolley V < MV M where the correct one is () A. Only (1) and (3) correct B. only (1) and (4) correct C. only (2) and (3) correct D. only (2) and (4) correct

The mass of the inclined trolley is m and the height is h. When an object with mass m slides down from the top of the trolley, the speed of the object sliding away from the bottom of the inclined trolley is set as V, regardless of all friction. The following statements are: ① the speed of the object sliding away from the trolley v = 2GH; ② the speed of the object sliding away from the trolley V < 2GH; ③ the speed of the object sliding away from the trolley v = MVM; ④ the speed of the object sliding away from the trolley V < MV M where the correct one is () A. Only (1) and (3) correct B. only (1) and (4) correct C. only (2) and (3) correct D. only (2) and (4) correct


According to the momentum conservation of the object and the car in the horizontal direction, if the right orientation is positive, we can get 0 = mv level - MV, so v = mv level M, because V level < V, so the speed of the car when the block slides away from the car is V < MVM, so ④ is correct; when the car is not moving, according to the conservation of mechanical energy, we can get MGH = 12mv2, so v = 2GH, because of the motion of the car, according to the conservation of energy, we can know that the speed of the block is V < MVM, so ④ is correct The speed of the block sliding away from the car is less than 2GH, so ② is correct



On the knowledge of physical momentum
Put a piece of white paper under a piece of wood, quickly pull hard, the block almost does not move, but slowly force is not like this! Why? Use momentum knowledge to answer!


The friction force acts on the wood block, f * t = MV (momentum change), which is quite right
If you pull slowly, the action accumulates and changes the state of the block



Throw an object with a mass of 1kg at the speed V level, and after throwing the object to the ground, what is its momentum change in 3 seconds before landing
That's all!


Because an object is only affected by gravity, the change of momentum is the change of impulse
Δ P = ft = Mgt = 1 * 10 * 3 = 30kg. M / s, vertically downward