Solution equation: 1.40% x = 24 2. X + one fifth x = 36 3. X-75% x 160 4.50% X-30% x = 18 5.80x-40x = 200 6. X + 120% x = 152 And to be neat! I'm in a hurry! Those are the first questions! Don't get me wrong!

Solution equation: 1.40% x = 24 2. X + one fifth x = 36 3. X-75% x 160 4.50% X-30% x = 18 5.80x-40x = 200 6. X + 120% x = 152 And to be neat! I'm in a hurry! Those are the first questions! Don't get me wrong!


1.40%X=24
0.4x24
x=24÷0.4
x=60
2. X + one fifth x = 36
1.2x=36
x=36÷1.2
x=30
3.X-75%X=160
0.25x=160
x=160÷0.25
x=640
4.50%X-30%X=18
0.2x=18
x=18÷0.2
x=90
5.80X-40X=200
40x=200
x=200÷40
x=5
6.X+120%X=152 !
2.2x=152
x=152÷2.2
x=760/11



36% x-2.18 = 3.82


0.36x - 2.18 = 3.82
0.36x = 3.82 + 2.18 = 6
36x = 600
x = 600/36 = 100/6 = 50/3



X △ 12 / 25 = 5 / 36


X △ 12 / 25 = 5 / 36
X × 25 / 12 = 5 / 36, both sides multiply by 36 at the same time
75X=5
X = 5 / 75
X = 1 / 15



The teacher copied an extracurricular exercise of an equation on the blackboard. The student on duty accidentally erased one of the numbers and made it (2x - *) / 3 - (2x + 1) / 4 = (10x + 1) / 6-1 (*). The math class representative calculated the erased number according to the teacher's answer x = 1 / 6. Please write down the calculation process of the math class representative


To avoid mixing the multiplication sign is * and the division sign is / erased, I use? To indicate that the denominator can be changed to 12, and the corresponding variable [4 * (2x -?)] / 12 - [3 * (2x + 1)] / 12 = [2 * (10x + 1)] / 12-12 / 124 * (2x -?) - 3 * (2x + 1) = 2 * (10x + 1) - 128x-4? - 6x-3 = 20x + 2-122x-4? - 3 = 20x-1018x = 7-4? Is carried in