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Solve the system of equations x = 2 = Y / 3 = Z / 4,5x + 2y-3z = 8, please
Let X / 2 = m then Y / 3 = Z / 4 = m so: x = 2m, y = 3M, z = 4m because 5x + 2y-3z = 8 so: 10M + 6m-12m = 8 M = 2 so x = 4, y = 6, z = 8 method 2: let X / 2 = m then Y / 3 = Z / 4 = m so: x = 2m, y = 3M, z = 4m because 5x + 2y-3z = 8 so: 10M + 6m-12m = 8 M = 2 so x = 4, y = 6, z = 8
X / 2 = Z / 4, Y / 3 = Z / 4, 5x + 3z-2y = 16 to solve the equations
x/2=z/4 y/3=z/4
x/2=y/3=z/4
Let X / 2 = Y / 3 = Z / 4 = K
x=2k
y=3k
z=4k
5x+3z-2y=16
5*2k+3*4k-2*3k=16
10k+12k-6k=16
16k=16
k=1
x=2k=2*1=2
y=3k=3*1=3
z=4k=4*1=4
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