![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Finding definite integral ∫ X / (x ^ 2 + 3x + 7) DX
Proof 1
(x^3-3x^2+3x)dx
=(x^4/4)-x^3+(3/2)x^2
Because: 1
Hello, can you help me with this problem? If ∫ (3x ^ 2 + k) DX = 1 / 2, then k =? This is the upper limit 1 and lower limit 0 of definite integral, please!
∫（3x^2+k）dx=∫ x^3+kx=1^3+k-0^3-0=1/2
k=-1/2
Definite integral of e ^ 2x + 1 / X on interval 1 to 2
What is the original equation of e ^ 2x + 1 / x
A:
∫ 1 to 2 (e ^ (2x) + 1 / x) DX
=E ^ (2x) / 2 + LNX | 1 to 2
=e^4/2+ln2-e^2/2-ln1
=e^2/2*(e^2-1)+ln2
RELATED INFORMATIONS
- 1. Solving indefinite integral ∫ sin2x × 3 ^ cosx ^ 2 × quadratic root sign (1 + 3 ^ cosx ^ 2 ×) DX
- 2. Given that the vertex of square-2x + m + 1 of the quadratic function y = x is the same as that of square + nx-1 of y = 2x, find the vertex value of M, n?
- 3. If the symmetry axis of the image of quadratic function f (x) is a straight line x = - 2, the intercept of the image on the Y axis is 1, and the length of the line segment cut by the X axis is 22, find f (x)
- 4. As shown in the figure, the image of quadratic function y = x ^ 2 + BX + C passes through a (- 1,0) and B (4,0), intersects with the positive half axis of Y axis at C, and ab = OC (1) Find the coordinates of point C (2) Find the expression of quadratic function, and find the maximum value of function
- 5. Let the minimum value of the quadratic function y = f (x) be 4, and f (0) = f (2) = 6, find the analytic expression of F (x)
- 6. Given the quadratic function f (x), when x = 2, there is a maximum value of 16. The length of the line segment obtained by cutting x-axis of its image is 8 If the quadratic function f (x) is known, when x = 2, it has a maximum value of 16. The length of the line segment obtained by its image cutting the x-axis is 8. The expression of F (x) can be obtained
- 7. Given that the quadratic function y = f (x), when x = 2, it has a maximum value of 16, and the length of the line segment obtained by its image cutting x-axis is 8. We try to prove that the equation f (x) = 0 has two unequal real values (1) It is proved that the equation f (x) = 0 has two unequal real roots, and the two roots are in the interval (- 3, - 1) and (5,7) respectively (2) The zero point of the function is obtained
- 8. Given that the image of quadratic function y = x2 + BX + C passes through point a (C, 0) and is symmetric with respect to line x = 2, the analytic expression of the quadratic function may be______ Just write a possible analytical expression
- 9. The quadratic coefficient a of quadratic function f (x) is known, and the solution set of F (x) > - x is (1,2). If the maximum value of F (x) is a positive number, then the value range of a is? RT, the answers on the Internet are different
- 10. (lesson 136 1 (2)) a, B, C are in equal proportion sequence, then the equation AX ^ 2 + BX + C = 0 (A) There must be two different real number roots. (b) there must be two same real number roots. (c) there must be no real number roots. (d) the above three cases can occur
- 11. 1 / 3 [3Y - (10-7y / 2)] - 1 / 6 [2Y - (2Y + 2 / 3)] = Y / 2-1
- 12. Answer question 2x-7y = 3,4x + 2Y = - 2
- 13. The first group of equations: 2x + y = 4,2y + Z = - 3,2z + x = 5, the second group of equations: X / 2 = Y / 3 = Z / 4,5x + 2y-3z = 8 Don't copy it
- 14. Solve the system of equations x = 2 = Y / 3 = Z / 4,5x + 2y-3z = 8, please
- 15. If the two roots of the equation AX ^ 2 + BX + C = 0 (a is not equal to 0) are 1, - 1 respectively, then 2A + C=
- 16. Solve the equation, 2x + 3Y = 1, x-2y = 3, try to judge the sign of the solution
- 17. The root of the equation 2Y ^ 2 = 3Y is
- 18. His father's age is 9 times that of XiaoCong, and his mother's age is 7.5 times that of XiaoCong. His father is 6 years older than his mother, and XiaoCong is a child this year______ I'm 40 years old
- 19. In solving the equation, Xiao Hua, a student of class 2, Grade 7, polluted a constant in the equation and could not see clearly. The polluted equation was 2y-1 / 2= 2y-1 / 2 = 1 / 2Y + [] how to do? Xiaohua thought about it, and then turned to the book to find that the solution is y = 5 / 3, so he made up the constant and finished the assignment. What's the constant? The equation and process and three grams of oil!
- 20. Xiao Ming did a problem of solving equation in his math homework. He accidentally polluted a constant in the equation. He couldn't see it clearly. The polluted equation was 2y-12 = 12Y - ● what should he do? Xiao Ming thought about it and then looked at the answer at the back of the book. The solution of the equation was y = - 53. Xiao Ming quickly made up the constant, which should be () A. 1B. 2C. 3D. 4