Answer question 2x-7y = 3,4x + 2Y = - 2
2x-7y=3(1)
4x+2y=-2(2)
(1)×2 4x-14y=6(3)
(2)-(3) 16y=-8
y=-½
Substituting (1) 2x + 3.5 = 3
x=-¼
{x = - # - 188;, y = - # - 189; is the solution of the original system of equations
10y-2(7y-2)=5(4y+5)
10y-2(7y-2)=5(4y+5)
10y-14y+4=20y+25
10y-14y-20y=25-4
-24y=21
y=-21/24
y=-7/8
1 / 3 (3Y - (10-7y) / 2) - 1 / 2 (2Y - (2Y + 2 / 3) = Y / 2-1 inclusion fraction
Y-(10-7Y)/6-Y+(Y+1/3)=Y/2-1
6Y-10+7Y-6Y+6Y+2=3Y-6
10Y=2
Y=1/5.
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