The teacher copied an extracurricular exercise of an equation on the blackboard. The student on duty accidentally erased one of the numbers and made it (2x - *) / 3 - (2x + 1) / 4 = (10x + 2) / 8-1 (*). The math class representative calculated the erased number according to the teacher's answer x = 1 / 6. Please write down the calculation process of the math class representative

The teacher copied an extracurricular exercise of an equation on the blackboard. The student on duty accidentally erased one of the numbers and made it (2x - *) / 3 - (2x + 1) / 4 = (10x + 2) / 8-1 (*). The math class representative calculated the erased number according to the teacher's answer x = 1 / 6. Please write down the calculation process of the math class representative

(2x-A)/3-(2x+1)/4=(10x+1)/6-1
(2*1/6-A)/3-(2*1/6+1)/4=(10*1/6+1)/6-1
(1/3-A)/3-(1/3+1)/4=(5/3+1)/6-1
(1/3-A)/3-1/3=1/3-1
(1/3-A)-1=-2
1/3-A=-1
A=1+1/3=4/3

When the teacher was correcting the homework, he found that when one student solved the equation 2x-1 / 3 = x + A / 3-1 to the denominator, the - 1 on the right side of the equation was not multiplied by 3, so he got the solution of the equation
For x = 2, please find out the value of a and help the student write out the correct process of solving the problem
The number is wrong. It should be {one student is solving the equation 2x-1 / 3 = x + A-1 / 3}

The wrong process is: 1. To get 2x-1 = x + A-1
2. Transform to 2x-x = A-1 + 1
3. When x = a, the result of the equation is x = 2, so a = 2
The correct process is: 1. To get 2x-1 = x + 2-3
2. Exchange left and right to get 2x-x = 2-3 + 1
3. X = 0

When Xiao Ming was doing the work of solving the equation, he accidentally polluted a constant in the equation. He couldn't see clearly. The polluted equation was 2Y + 1 / 2 = 1 / 2Y-

2Y + 1 / 2 = you can multiply both sides by 1 / 4 to get 1 / 2Y + 1 / 8, which is equal to 1 / 2Y - (- 1 / 8), so the answer is - 1 / 8