The teacher copied an extracurricular exercise of an equation on the blackboard. The student on duty accidentally erased one of the numbers and made it (2x - *) / 3 - (2x + 1) / 4 = (10x + 2) / 8-1 (*). The math class representative calculated the erased number according to the teacher's answer x = 1 / 6. Please write down the calculation process of the math class representative
(2x-A)/3-(2x+1)/4=(10x+1)/6-1
(2*1/6-A)/3-(2*1/6+1)/4=(10*1/6+1)/6-1
(1/3-A)/3-(1/3+1)/4=(5/3+1)/6-1
(1/3-A)/3-1/3=1/3-1
(1/3-A)-1=-2
1/3-A=-1
A=1+1/3=4/3
When the teacher was correcting the homework, he found that when one student solved the equation 2x-1 / 3 = x + A / 3-1 to the denominator, the - 1 on the right side of the equation was not multiplied by 3, so he got the solution of the equation
For x = 2, please find out the value of a and help the student write out the correct process of solving the problem
The number is wrong. It should be {one student is solving the equation 2x-1 / 3 = x + A-1 / 3}
The wrong process is: 1. To get 2x-1 = x + A-1
2. Transform to 2x-x = A-1 + 1
3. When x = a, the result of the equation is x = 2, so a = 2
The correct process is: 1. To get 2x-1 = x + 2-3
2. Exchange left and right to get 2x-x = 2-3 + 1
3. X = 0
When Xiao Ming was doing the work of solving the equation, he accidentally polluted a constant in the equation. He couldn't see clearly. The polluted equation was 2Y + 1 / 2 = 1 / 2Y-
2Y + 1 / 2 = you can multiply both sides by 1 / 4 to get 1 / 2Y + 1 / 8, which is equal to 1 / 2Y - (- 1 / 8), so the answer is - 1 / 8