A and B solve the system of equations ax + by = 2, mx-7y-8 = 0. A right solution leads to x = 3, y = - 2. B wrongly writes m, and solves x = - 2, y = 2. Find a, B, M

A and B solve the system of equations ax + by = 2, mx-7y-8 = 0. A right solution leads to x = 3, y = - 2. B wrongly writes m, and solves x = - 2, y = 2. Find a, B, M

According to the meaning of the title
3a-2b=2 (1)
3m+14=8 (2)
-2a+2b=2 (3)
From (2), M = - 2
(1) + (3) gives a = 4
Substituting a = 4 into (1) yields B = 5
∴a=4,b=5 ,m=-2

A and B solve the system of equations ax + by = 2 mx-7y = 8 at the same time. A solves it correctly and gets x = 3 y = - 2,
A and B solve the system of equations ax + by = 2 mx-7y = 8 at the same time. A solves it correctly and gets x = 3 y = - 2. B writes m wrong and gets x = - 2 y = 2 to find the value of a, B and m (if there is a process, it's better to type. I may not see it in the picture.)

3a-2b = 2 ① 3m+14=8…… ② -2a+2b=2…… ③
M = - 2
① A = 4
The solution of a = 4 generations is: 12-2b = 2, B = 5

Given that k > 0, the binary quadratic equation kxy + x ^ 2-x + 4y-6 = 0 represents two straight lines, and the value of K is obtained

Let these two lines be a1x + b1y + C1 = 0 and a2x + b2y + C2 = 0
By multiplying the two formulas, we get: a1a2x ^ 2 + b1b2y ^ 2 + (A1B2 + A2B1) XY + (a1c2 + a2c1) x + (b2c1 + b1c2) y + C1C2 = 0
Therefore, the following four formulas are obtained
a1a2=1
a1c2+a2c1=-1
b2c1+b1c2=4
c1c2=-6
The result of multiplication of two three two formulas is as follows:
(A1B2 + A2B1) C1C2 + a1b1c2 ^ 2 + a2b2c1 ^ 2 = - 4
From the second formula: A1 = a2c1 / C2, A2 = a1c2 / C1, this is the 672 formula
By substituting the first 467 into the fifth, we can get
a1b2+a2b1=1/3
And K = A1B2 + A2B1
So k = 1 / 3

Given y = 13x-1, then the value of 13x2-2xy + 3y2-2 is______ ．

∵y=13x-1，∴13x2-2xy+3y2-2=13（x2-6xy+9y2）-2=13（x-3y）2-2=13×9-2=1．