If s = 2x = Y-Z, the range of S is obtained

3x+2y=5-z
x+y=2+z
Taking Z as a known number, the solution is x = 1-3z, y = 1 + 4Z
So 1-3z, 1 + 4Z, Z are all nonnegative numbers, and the solution is 0

Find X: Y: Z for known equations {x + y-7z = 0 (1) 3x-2y-z = 0 (2) and Z is not equal to 0

The solution is x + y-7z = 0
We get x + y = 7z
From 3x-2y-z = 0
We get 3x-2y = Z. ②
From (1) × 2 + (2)
5X=15Z
The solution is x = 3Z
Substituting x = 3Z into (1)
The solution is y = 4Z
That is, x = 3Z, y = 4Z,
So x: Y: z = 3:4:1

Given point P (a ^ 2-A, 1) in inequality x + y

P (a ^ 2-A, 1) in inequality x + y

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