If the projection of origin o on line L is point H (- 2,1), then the equation of line L is Please don't use the slope method. We haven't learned that yet. Use the normal vector or direction vector method

If the projection of origin o on line L is point H (- 2,1), then the equation of line L is Please don't use the slope method. We haven't learned that yet. Use the normal vector or direction vector method


Since the vector Oh = (- 2,1), the direction vector (perpendicular to OH) can be (1,2). According to the parametric equation, the equation of the straight line l can be obtained as follows:
X = - 2 + T, y = 1 + 2T, the elimination parameter is 2x-y + 5 = 0



When the line L passes through the point m (2,1) and intersects the positive half axis of x-axis and y-axis at two points a and B respectively, O is the coordinate origin. (I) when the area of △ OAB is the smallest, the equation of line L is obtained. (II) when | Ma | · | MB | is the minimum, the equation of line L is obtained


(1) Let the linear equation l be XA + Yb = 1 (a, B are positive numbers), ∵ l pass through the point m (2, 1), ∵ 2A + 1b = 1. ∵ 1 = 2A + 1b ≥ 22a · 1b, then ab ≥ 8 is obtained. If and only if 2A = 1b, i.e. a = 4, B = 2, the equal sign holds. If a = 4, B = 2, AB has the minimum value of 8, and △ OAB area is s = 12ab =



-Are 3xy and y of the same kind


No