If the area of △ AOB (o is the coordinate origin) is 2, then the value of B is?

If the area of △ AOB (o is the coordinate origin) is 2, then the value of B is?

Because the area of △ AOB (o is the coordinate origin) is 2,
So ob = 2 (because 2 × 2 △ 2 = 2), so B (0,2)
Substituting a (- 2,0) and B (0,2) into y = KX + B
We get 0 = - 2K + B, 2 = B, k = 1
So y = x + 2. B = 2

A straight line y = KX + B passes through point a (- 2,0) and a point B on the positive half axis of Y axis. If the area of △ AOB (o is the origin of the coordinate) is 2, the analytical expression of the straight line is obtained
If the distance is less than 4km, there will be a starting fee of 8 yuan. If the distance is more than 4km, there will be an additional fee of 1.8 yuan. When the distance is more than 4km, write out the functional relationship between Y (yuan) and X (km), and point out what function it is, and what is the value range of the independent variable x?
If the distance of a taxi is less than 4km, there will be a starting fee of 8 yuan. If the distance is more than 4km, there will be an additional fee of 1.8 yuan for every 1km. When the distance is more than 4km, the functional relationship between the fee y (yuan) and the mileage x (km) will be written. What is the function and the value range of the independent variable x?

Because the area of △ AOB is 2
So OA * ob * 1 / 2 = 2
2*OB*1/2=2
OB=2
Because the line y = KX + B intersects the Y axis at B
The coordinates of B are (0,2)
Substituting a (- 2,0) and B (2,0) into
The solution is k = 1
The analytical formula of the line x + 2 = y

A straight line passes through point a (- 1,5) and is parallel to y = - X. if point B (m, - 5) is on this straight line and O is the origin of coordinates, the area of △ AOB can be obtained
A straight line passes through point a (- 1,5) and is parallel to y = - X. if point B (m, - 5) is on this straight line and O is the origin of the coordinate, calculate the area of △ AOB

Because a is parallel to the line y = - X
So the square of the line L passing through a is called y = - x + 4
B (9, - 5) is called by bringing B into the square
Line AB intersects X axis at C, C (4,0)
S=Soca+Socb=4*5*(1/2)+4*5*(1/2)=20

The straight line L passes through the point m (2,1), and intersects with the non negative half axis of X axis, the non negative half axis of Y axis at two points P and Q respectively, and point O is the origin of coordinates
The equation for finding the line L with the minimum poq area of triangle

Solution 1 Let P (a, 0). Q (0, b). Then the linear equation: X / A + Y / b = 1. The triangle area is 1 / 2Ab. Substituting the point m (2,1) to get 2 / A + 1 / b = 1. Using the basic inequality 2 / A + 1 / b ≥ 2 radical sign 2 / A * 1 / B, i.e. 1 ≥ 2 radical sign 2 / A * 1 / B, we get ab ≥ 8. If and only if 2 / a = 1 / B, we take the equal sign