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Three cubes with a surface area of 54 square centimeters are put together to form a cuboid. What is the surface area of this cuboid By 7:3, come on
54/6=9(cm2)
9x(6x3-4)=9x14=126(cm2)
Put four small cubes together into a cuboid, the surface area is reduced by 54 square centimeters. Find the surface area and volume of each cuboid
Put 4 small cubes together into a cuboid, and reduce the surface area by 6 faces
One surface area of cube = 54 △ 6 = 9 square centimeter
The edge length of cube is 3 cm
Cube surface area = 9 × 6 = 54 square centimeter
The surface area of the cuboid is 54 × 4-54 = 162 square centimeters
Cuboid volume = 9 × 3 × 4 = 108 CC
After a cube with a surface area of 54 square centimeters is cut into two identical cuboids, what is the maximum sum of the surface areas of the two cuboids
54 + 54 divided by 6x2 = 72 square centimeters
The surface area of a cube is 54 square centimeters. Divide it into two cuboids equally. The surface area of each cuboid is______ Square centimeter
54 △ 6 = 9 (square centimeter), and because 3 × 3 = 9 (centimeter), the edge length of the cube is 3cm; then the length, width and height of the cuboid are 3, 3 and 1.5cm respectively, and the surface area of the cuboid is (3 × 3 + 1.5 × 3 + 3 × 1.5) × 2, = 18 × 2, = 36 (square centimeter); answer: the surface area of each long cuboid is 36 square centimeter; so the answer is: 36
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