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Saw a cube with an edge length of 3 decimeters into two cuboids. What is the sum of the surface areas of the two cuboids?
3*3*6+2（3*3）=72
Saw the 1.2-meter-long rectangle into three small cubes, and the surface area increased by 64 square decimeters. Now we need to find the surface area of the original cuboid quickly
Analysis: rectangular saw into three small cube, the surface area increased by 64 square decimeters, in fact, increased by four bottom area;
The bottom area of the original cuboid: 64 △ 4 = 16
The original cuboid's width = height = 4 (decimeter)
1.2 m = 12 decimeters
The surface area of the original cuboid = (12 × 4 + 12 × 4 + 4 × 4) × 2 = 224 (decimeter & sup2;)
A: the surface area of the original cuboid is 224 decimeters & sup2
A cube has a surface area of 24 square decimeters. Divide it into two cuboids averagely. How many square decimeters is the surface area of each cuboid?
Just say the formula, not the equation
Don't talk about the method, just the formula
16
The sum of six faces of cube and six faces of cuboid is equal to the area of four faces of cube, s = 4 * 24 / 6 = 16
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