A cube with a surface area of 54 square decimeters is sawn into two cuboids. The sum of the surface areas of the two cuboids is () square decimeters A. 108B. 72C. 54

A: the sum of the surface areas of the two cuboids is 72 square decimeters

The surface area of a cuboid is 45 square decimeters. It can be sawed into two equal cubes. The surface area of this cube is______ ．

A: the surface area of this cube is 27 square decimeters. So the answer is: 27 square decimeters

What is the surface area of each cuboid

The surface area of the two cuboids is two more than that of the cube, and the bottom area is 6 * AA + 2AA = 8AA
The surface area of each cuboid is 4AA square decimeter

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