2t-3s = - 5 3T + 2S = 12 to solve binary linear equations

2t-3s = - 5 3T + 2S = 12 to solve binary linear equations

2t-3s = - 5 d 3T + 2S = 12 e multiply D equation by 3 and e equation by 2 to make 6t-9s = - 15 d 6T + 4S = 24 e subtract e - 13s = - 39 s = 3 from D and substitute s = 3 into D 6t-9 * 3 = - 156 t-27 = - 156 t = 27-156 t = 12 T = 2, so t = 2 s = 3 is detailed enough. Let's use my mobile phone. It's hard for me to call

If points a (t-3s + 2S), B (14-2t + s, 3T + 2s-2) are symmetric about the X axis, find the values of S and t

On X-axis symmetry
The abscissa is equal and the ordinate is opposite
t-3s=14-2t+s
-2s=3t+2s-2
s=-5/2,t=4

Solutions of 3s-t = 5S + 2T = 15 equations

3s-t = 5; t = 3s-5; substitution
5S + 2T = 15; 5S + 2 × (3s-5) = 15;
That is: 11s-10 = 15;
S = 25 / 11;
Then t = 3s-5 = 3 × 25 / 11-5 = 20 / 11;

The solutions are as follows: (1) 3x − 2Y = 9x − y = 7; (2) 5m − 2n = − 7 − 3M + 2n = 9

(1) 3x − 2Y = 9 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; ① x − y = 7 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; ②, get from ②; X = 7 + y ③, substitute ③ into ①, get: 3 (7 + y) - 2Y = 9, get: y = - 12, and then substitute

Solve the equations 4m + 5N = 75m − 4N = − 22

① The solution of the original equations is m = - 2n = 3

There is a system of equations 5m + 2n = 11; 3m-2n = 13

The sum of the two equations gives 8m = 24
The solution is m = 3
Substituting M = 3
Get n = - 2

Is X-1 under the root sign the same as X-1 under the root sign

It's not the same
The definition field of X √ (x-1) is x ≥ 1
The definition field of √ X & # 178; (x-1) is x = 0 or X ≥ 1

Is X-2 under y = radical * x + 2 under radical and the square-4 of X under y = radical the same function?
Why can't the definition field of X + 2 under y = root sign X-2 * root sign x + 2 be greater than or equal to - 2

Two root signs mean both
So X-2 ≥ 0 and X + 2 ≥ 0
The two were established at the same time
Take the big one
So x ≥ 2
And the square of X under the root sign is - 4
Then only X & # 178; - 4 ≥ 0
So it can also be x ≤ - 2
So the two functions are not the same

Is root 3 a square root or a monomial

The positive one of the square roots is the arithmetic square root, so it should be said that the root sign 3 is the arithmetic square root of 3;
Definition of monomial: algebraic formula without plus and minus sign (algebraic formula of product of number and letter), a single number or letter is also called monomial!
So root 3 is a monomial, no problem

Can you add a monomial to the polynomial x2 + 4 to make it a complete square? There are several methods ()
A. 2B. 3C. 5D. 6

① When X2 is a square term, X2 ± 4x + 4 = (x ± 2) 2, the added monomial is 4x or - 4x; ② when X2 is a product double term, 116x4 + x2 + 4 = (14x2 + 2) 2, the added monomial is 116x4; ③ if it is the square of the monomial, the added term is - x2 or - 4