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If the solution of X + 4Y = 2k-1,3x-y = 2K is also the solution of 2x + 3Y = 6, the value of K is obtained
∵x+4y=2k-1
3x-y=2k
∴x=(10k-1)/13
y=(4k-3)/13
According to the meaning of the title:
2×[(10k-1)/13]+3×[(4k-3)/13]=6
20k-2+12k-9=78
32k=89
∴k=89/32
The sum of solutions of the equations {2x + 3Y = a-2,5x-y = a + 1 is 5, and the value of a is obtained
On the equation. Detailed requirements
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2X+3Y=A-2 ---①
5X-Y=A+1 ---②
① Formula * 6: 12x + 18y = 6 * (A-2) --- ③
② + 3: 17x + 17Y = 6 * (A-2) + (a + 1), that is, 17 (x + y) = 6 * (A-2) + (a + 1)
Since the sum of its solutions is 5, that is, x + y = 5, then it is substituted: 17 * 5 = 6 * (A-2) + (a + 1),
So a = 96 / 7
If the sum of solutions of the equations 2x + 3Y = a-2,5x-y = a + 1 is 5, the value of a is obtained
From the equations 2x + 3Y = a-2,5x-y = a + 1, it is concluded that
x=(4a+1)/17,y=(3a-12)/17
From x + y = 5
=(4a+1)/17+3a-12)/17=5
a=96/7
Solving the equations {2x + 3Y = 7, 5x-3y = 7
2x + 3y = 7
5x - 3y = 7
Add the two expressions to get the
7x = 14
x = 2
such
2x + 3y = 4 + 3y = 7
3y = 3
y = 1
Equations
x = 2 ,
y = 1 .
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