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The perimeter of the bottom surface of a cone-shaped sand pile is 25.12m and the height is 1.5m. If the weight of each cubic meter of sand is 1.7t, how much is the weight of the pile? (the number is reserved to one decimal place)
Radius of cone = 25.12 △ 3.14 △ 2 = 4m
Volume = 3.14 × 4 & # 178; × 1.5 × 1 / 3 = 25.12 M3
Weight = 25.12 × 1.7 ≈ 42.7 tons
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A cone-shaped sand pile, 5 meters long, with a bottom circumference of 25.12 meters, weighs 1.7 tons per cubic meter of sand. How many tons does this pile of sand weigh
What is the radius of the bottom
25.12 ﹣ 3.14 ﹣ 2 = 4m
What's the volume of sand
4 × 4 × 3.14 × 1.5 × 1 / 3 = 25.12 M3
This pile of sand is about heavy
1.7 × 25.12 = 42.704 tons ≈ 43 tons
There is a conical sand pile with a bottom area of 6 square meters and 5 meters. How thick can a sand pit with a length of 5 meters and a width of 3 meters be paved with this pile of sand
In a hurry.
Volume = 6 × 1.5 × 1 / 3 = 3 m3
Thickness = 3 ﹣ 5 ﹣ 3 = 0.2m
The bottom area of a cone-shaped sand pile is 12.56 square meters and its height is 0.6 M. how thick can the sand pile be laid into a sand pit with a length of 4.5 m and a width of 3 m
(to percentile)
Thickness that can be paved
=Volume of cone (4.5 × 3)
=1 / 3 × 12.56 × 0.6 △ 13.5
About 0.19M
How high does it take to dump a conical sand pile with a diameter of 6m or 5m into a circular sand pit with a diameter of 3M?
Explain the solution
[Question supplement: explain the solution]
The volume of conical sand pile is v = 1 / 3 × π × R ^ 2 × h, where R ^ 2 is the square of the radius of the bottom circle of the cone and H is the height of the center line of the cone
The diameter of the bottom surface of conical sand pile is 6 meters, so the radius r = 6 △ 2 = 3 meters
Also: height of conical sand pile H = 2.5m
Ψ v = 1 / 3 × π × R ^ 2 × H = 1 / 3 * π * 3 ^ 2 * 2.5 = 7.5 π M3
The volume of sand in the cylindrical sand pit is v = π × R ^ 2 × h, where R ^ 2 is the square of the radius of the bottom circle of the cylindrical sand pit, and H is the depth of filling the cylindrical sand pit
The diameter of the bottom circle of the cylindrical sand pit is 3M, so the radius r = 3 △ 2 = 1.5m
According to v = π R ^ 2H
The depth of filling cylindrical sand pit is h = V / (π R ^ 2) = 7.5 π / (π * 1.5 ^ 2) = 10 / 3 ≈ 3.33 M
A conical sand pile has a bottom area of 12.56 square meters and a height of 9 square decimeters. If the sand pile is laid into a sand pit with a length of 5m and a width of 2m, how thick can it be laid?
The height is 9 decimeters
9 decimeters = 0.9 meters
12.56 × 0.9 × 1 / 3 (5 × 2) = 0.3768m
3768m
A cone-shaped sand pile with a bottom circumference of 12.56m and a height of 1.2m is laid in a cylindrical sand pit with a bottom diameter of 4m and a height of 3M,
How thick can it be?
Cone volume = area of cylinder bottom × thickness
Cylinder radius = 4 △ 2 = 2m
So:
Thickness that can be paved
=Cone volume (area of cylinder bottom)
=(1 / 3 × 12.56 × 1.2) / (3.14 × 2 & # 178;)
=0.4m
A cone-shaped sand pile has a bottom area of 3.6 square meters and a height of 2 meters. How thick can this pile of sand be laid in a sand pit with a length of 4 meters and a width of 2 meters?
Answer in 20 minutes
The volume of sand is:
V=1/3×S×h=1/3×3.6×2=2.4m^3
The bottom area of sand pit is:
S bottom = 4 × 2 = 8m & # 178;
Ψ H = V / s bottom = 2.4 / 8 = 0.3m
That is to say, it can be laid with a thickness of 0.3m
A conical sand pile with a bottom area of 12.56 and a height of 0.9 meters. How thick can this pile of sand be laid into a sand pit with a length of 4.5 meters and a width of 2 meters?
(13 × 12.56 × 0.9) / (4.5 × 2) = 3.768 ／ 9, ≈ 0.42 (m). A: the sand can be paved about 0.42 m thick
A cylindrical sand pile has an area of 12.56 cubic meters and a height of 0.9 meters. How many meters can we lay this pile of sand into a sand pit with a length of 4.5 meters and a width of 2 meters?
Keep two decimal places~
The volume is: 12.56 × 0.9 △ 3 = 3.768 cubic meters
You can shop:
3.768÷4.5÷2
=3.768÷9
About 0.42m
If you have any questions, please ask,
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