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If the edge length of a cube increases four times, its surface area will increase______ Double, volume expansion______ Times
According to the analysis, the edge length of the cube is increased by 4 times, the surface area is increased by 4 times, that is, 4 × 4 = 16 times; the volume is increased by 4 times, that is, 4 × 4 × 4 = 64 times
Carpet is laid on the surface of a staircase with a height of 6cm and a length of 10cm, and the width of the staircase is 3M
0.1*3+0.06*3=0.48m^2
The width of a stairway is 2m, and its side is as shown in the figure, ab = 6m, BC = 3M. Now if you want to lay carpet on the surface of the stairway, how many square meters of carpet should you buy at least?
Because the sum of height = BC, the sum of width = AB, the length = 2
Therefore, the area of his blanket = 2Ab + 2BC = 2 × (6 + 3) = 18
As shown in the figure, when carpet is laid on the stair surface with a height of 2M and a horizontal distance of 3M, how many meters is the length of carpet required at least?
As shown in the figure, in a right triangle, the length of the carpet is the length of the oblique side
From the Pythagorean theorem, we get that,
The hypotenuse is √ (2 & # 178; + 3 & # 178;) = √ 13 ≈ 3.6 (m)
It is known, as shown in the figure, what is the minimum length of carpet required for laying carpet on the stair surface with 3M high and 30 ° slope angle
About 9 m less than. 3 M + 3 times the root 3
As shown in the figure, on the surface of the stairs with a height of 2M and a horizontal distance of 3M, how many meters does the carpet need at least? The detailed process is required
It's 2 + 3 = 5 meters
Because the length of the stairs = the horizontal distance
Height of stairs = 2m high
A pool is 20 m long, 10 m wide and 2 m deep. How many square tiles with side length of 1 DM are needed to build around the pool and the bottom
If you want to know how many pieces you need, you have to first calculate the surface area of the pool: (20 × 10 + 10 × 2 + 2 × 20) × 2 = 520 (m ᦉ 178;) because the pool has only five sides, you need to subtract the area of the top side: 520-20 × 10 = 320 (m ᦉ 178;) because the unit of the side length of the ceramic tile is different from the unit of the surface area of the pool, you need to convert
The bottom of a pool is square, the side length of the bottom is 5m, and the depth is 2m?
5 × 5 + 5 × 2 × 4 = 25 + 40 = 65 (M2)
Answer: the area that sticks ceramic tile is 65 square metre
In a 30 meters long, 10 meters wide, 2.2 meters deep cuboid reservoir, tile is a square with side length of 0.2 meters?
The area to be tiled: 30 × 10 + 30 × 2.2 × 2 + 10 × 2.2 × 2, = 300 + 132 + 44, = 476 (square meters); the number of tiles to be tiled: 476 ^ (0.2 × 0.2) = 11900 (pieces); a: at least 11900 tiles are required after the reservoir is tiled
In a cuboid cistern of 20 m long, 8 m wide and 1.5 m deep, tile is a square with side length of 0.2 M
How many fast tiles do you need to cover all the sides and bottom of the pool?
Area around and bottom of cuboid reservoir: 20 * 8 + 20 * 1.5 * 2 + 8 * 1.5 * 2 = 244 (M2)
Area of ceramic tile: 0.2 * 0.2 = 0.04 (M2)
Therefore, tile: 244 / 0.04 = 6100 (pieces) is needed to paste around and at the bottom of the pool
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