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A cuboid wood, its cross section is a cube with side length of 4 decimeters, wood length of 3 meters, how many cubic meters is its volume
4 decimeters = 0.4 meters
Volume = 0.4 × 0.4 × 3 = 0.48 M3
1、 There are 5 steps in front of the gate of the school teaching building, each step is 6 meters, 0.3 meters wide and 0.2 meters high
1) How many square meters does the five steps cover?
(2) To pave these steps with ceramic tiles (two sides also need to be paved, but not behind), it needs 80 fast tiles per square meter, how many fast tiles do you need in total?
(3) To build these five steps with bricks, it needs 108 fast bricks per cubic meter, at least how many fast bricks?
0.5 * 5 * 6 = 15 square meters
15 * 80 = 1200 yuan
15 * 108 = 1620 fast
There are five steps in front of the school library. Each step is 4 meters long, 0.3 meters wide and 0.2 meters high. (1) how many square meters does the five steps cover? (2)
How many square meters of floor tiles are needed to pave the surface of these five steps?
The first question: if we calculate the area of this step, we can take it as "lay five rectangles 4 meters long and 0.3 meters wide into a large rectangle, and calculate the area of the large rectangle". In this way, the problem is easy to do
4×0.3×5
=1.2×5
=6（m²）
Answer: how many 6 square meters does 5 steps cover
Question 2: (4 × 0.2 + 4 × 0.3) × 5
=（0.8+1.2）×5
=2×5
=10（m²）
Answer: need floor tile of 10 square metre at least
It should be like this, I hope my answer can bring you some help, I wish you progress in learning!
There are 8 steps in front of the gate of the school library. Each step is 10 meters long, 0.4 meters wide and 0.3 meters high. How much does the 8 steps cover
The area of each step is 10x0.4 = 4 m2, and the total area of 8 steps is 8x4 = 32 m2
As shown in the figure, in a basketball game, player a jumps up and shoots. It is known that the ball is 20 / 9m above the ground when it is released, and the horizontal distance from the center of the basket is 7m
In a basketball match in grade nine of LiZhi middle school, as shown in the picture, player a is shooting and the ball is known to be off the ground when it is released
twenty
nine
m. The horizontal distance from the center of the basket is 7 m, the known trajectory of basketball is parabola, and the distance between the basket and the ground is 3 m
(1) Establish the plane rectangular coordinate system as shown in the figure, ask whether the basketball can accurately hit?
(2) At this time, if the opposing team member B jumps to block the block 1m in front of a, and the maximum touch height of B is known to be 2.9m, then whether he can block the block successfully or not, and explain the reason
(1) Let the analytic expression of the function be y = a (X-H) ² + K
(4,4) substitution
y=a(x-4)²+4（0≤x≤8）
(0,20 / 9) substituting
20/9=a(0-4)²+4
So a = - 1 / 9
So y = - 1 / 9 (x-40 & # 178; + 4 (0 ≤ x ≤ 8)
Y20 / 9 when x = 8
9/20＜3
So I couldn't make it
(2) It's not going to work
Because when x = 1, y = - 1 + 4 = 3
3＞2.9
So it can't be successful
I'm very happy to be able to answer for you
Yang
In a basketball game, player a is throwing the ball. It is known that the ball is 20 / 9 meters above the ground when it is released, and the horizontal distance between the ball and the center of the hoop is 7 meters. When the ball is released, it will go into the water
It's a complicated problem,
In a basketball game, player a jumps up and shoots. As shown in the figure, the horizontal distance between the ball and the basket center C is 7m when the ball is released at position A. when the horizontal distance between the ball and the basket center C is 4m, the maximum height is 4m (position B), and the basketball running route is parabola. The basket is 3M from the ground? ② At this time, the opposing player B comes to block the shot. It is known that the maximum height he touches after jumping is 3.19M. What can he do to block the shot successfully?
① Firstly, the coordinate system is established. From the meaning of the problem, a (0209) and vertex B (4,4) are obtained. The analytic formula of the parabola is y = a (x-4) 2 + 4, ∧ 209 = a (x-4) 2 + 4. The solution is a = - 19. ∧ y = - 19 (x-4) 2 + 4. When x = 7, y = 3. ∧ the ball can hit accurately. (2) the analytic formula of the function obtained from (1), when y = 3.19, 3.19 = - 19 (x-4) 2 + 4, the solution is X1 = 6.7 (not in line with the reality, If you want to block, you must block before the basketball drops, otherwise it is invalid). X2 = 1.3. When the distance between player B and player a is less than 1.3 meters, you can block successfully
In a basketball game, player a jumps up and shoots. It is known that the ball is 20 / 9 m from the ground and the horizontal distance from the center C of the basket
When the horizontal distance of the ball is 4 meters, the maximum height is 4 meters. Set the basketball running track as a parabola, and the hoop is 3 meters from the ground (1)
(2) Can this basketball hit?
The horizontal distance from the basket center C is 8 meters, if it is 8 meters
Let y = a (x-4) & sup2; + 4
Over (0,20 / 9)
16a+4=20/9
a=-1/9
∴y=-1/9（x-4）²+4
(2) Substituting x = 8 into y = - 1 / 9 (x-4) & sup2; + 4
y=20/9≠3
Miss
Application of quadratic function: in a basketball game, Xiao Ming jumps up and shoots. He knows that the ball is 20 / 9 meters high from the ground when it is released, and the horizontal distance from the center of the hoop is 8 meters,
In a basketball game, Xiao Ming jumps up to shoot. He knows that the ball is 20 / 9 meters high from the ground when it is released, and the horizontal distance from the center of the hoop is 8 meters. When the ball is released, the horizontal distance is 4 meters, and the maximum height is 4 meters. Suppose the trajectory of the basketball is a parabola, and the center of the hoop is 3 meters away from the ground, then ask whether it can be put in? Or I will not know
Let the parabola be the square of y = KX + m, and set up a rectangular coordinate system. Let the release point be a (0,20 / 9), the highest point be B (4,4), and the rebound point be C (8,3)
How many cm long rope is needed to tie four wine bottles with a bottom radius of 4cm tightly for one circle?
Length: 2 × 3.14 × 4 + (4 + 4) × 4 = 57.12 cm
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